Hi everyone, This is what the dataset looks like
| ID | DATE | VALUE |
| 1 | 2022-11-20 | 10 |
| 1 | 2022-11-22 | 10 |
| 2 | 2022-11-12 | 20 |
| 2 | 2022-11-18 | 20 |
| 2 | 2022-11-25 | 20 |
| 3 | 2022-11-21 | |
| 3 | 2022-11-24 | |
| 3 | 2022-11-27 |
I would like to have the result like this
| ID | DATE | VALUE | DIF |
| 1 | 2022-11-20 | 10 | |
| 1 | 2022-11-22 | 10 | 2 |
| 2 | 2022-11-12 | 20 | |
| 2 | 2022-11-18 | 20 | 6 |
| 2 | 2022-11-25 | 20 | 13 |
| 3 | 2022-11-21 | ||
| 3 | 2022-11-24 | ||
| 3 | 2022-11-27 |
So if VALUE is same in the same group which is the ID, then I need get the difference of Date between the first date in the group and the other date in the group. And if VALUE is blank, then I do not need the difference. I have tried use "if value ^=. and value ne first.value" then get value difference, but it will get wrong answer. Please help!
Thanks so much
Try this
data have;
input ID DATE :yymmdd10. VALUE;
infile datalines missover;
format DATE yymmdd10.;
datalines;
1 2022-11-20 10
1 2022-11-22 10
2 2022-11-12 20
2 2022-11-18 20
2 2022-11-25 20
3 2022-11-21
3 2022-11-24
3 2022-11-27
;
data want(drop = d);
set have;
by ID;
if first.id then d = date;
if VALUE & first.ID = 0 then dif = date - d;
retain d;
run;
Result:
ID DATE VALUE dif 1 2022-11-20 10 . 1 2022-11-22 10 2 2 2022-11-12 20 . 2 2022-11-18 20 6 2 2022-11-25 20 13 3 2022-11-21 . . 3 2022-11-24 . . 3 2022-11-27 . .
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