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azee007
Calcite | Level 5
I used a really simple solution-It worked ...But need input if any

length birthdied $15;
if died ='' then birthdied =scan(birth,-1,'/,')||'-';
else birthdied = scan(birth,-1,'/,')||'-'||scan(died,-1,'/,');
Shmuel
Garnet | Level 18
If you compare my last post to some previous you will find exact code written before.
azee007
Calcite | Level 5
Dear Shmuel,

Can you please explain me in much simpler form , as i couldnt understand what you are trying to tell me . I have been working on this code now for a long time ...but the requirement that :

Should be calculated as birthyear-deadyear if both values are present and
birthyear - if the person is still present.

My data given is dates of birth and dead in the form mm/dd/yyyy and some dates in yyyy.
I need to handle both cases.

I also want that the not equal relation can be specified using ^= or ne in case it is needed.
Shmuel
Garnet | Level 18

Here is just the last datastep with some remarks added:

I have just noticed a typo: you created variable DEAD but used variable DIED. 

I have changed it into - in bold letters - died.

 

data want;
  set have;

        length birthdead $10;                                         /* assigning length to the new variable to create which shoulb be 

                                                                                        in a format of:  YYYY-YYYY or just YYYY */
        %dt_convert(birth_x , birth);                              /* converting birth date from character to SAS numeric date */
        %dt_convert(dead_x , died);                           /* converting death date from character to SAS numeric date */
        if died = . then birthdead = put(year(born,4.);   /* assigning result value when no death date  =  just birth YYYY */
        else birthdead = catx('-' , year(birth), year(died));  /* assignung result as BIRTH-DEATH years: YYYY-YYYY */

                                                                                             /* instead CATX function yo can write:                                    */

                                                                                              /*  left(year(birth)) || '-' || left(year(died))                           */
       drop birth_x dead_x;                                           /* dropping that variables as not needed to keep on output */

run;

azee007
Calcite | Level 5
Do i have to use
%macro dt_convert (dtx , dt);
if length(&dtx) = 4
then &dt = mdy(01,01,input(&dtx,4.));
else &dt = input(&dtx , mmddyy10.);
%mend dt_convert;

as i am using above code before the new code and still getting the same log erros

if died = . then birthdead = put(year(birth,4.); /* assigning
_
22
3 The SAS System 16:08 Sunday, November 6, 2016

76
68 ! result value when no died date = just birth YYYY */
ERROR 22-322: Syntax error, expecting one of the following: !, !!, &, *, **, +,
',', -, /, <, <=, <>, =, >, ><, >=, AND, EQ, GE, GT, IN, LE, LT,
MAX, MIN, NE, NG, NL, NOT, NOTIN, OR, ^, ^=, |, ||, ~, ~=.

ERROR 76-322: Syntax error, statement will be ignored.
Shmuel
Garnet | Level 18

data want;
  set have;

        length birthdead $10;                                        

                                                                                       
        %dt_convert(birth_x , birth);                              
        %dt_convert(dead_x , died);                           
        if died = . then birthdead = put(year(born,4.),4.);    /* sorry, my typo: correct this line: all brackest should be even)
        else birthdead = catx('-' , year(birth), year(died));  
       drop birth_x dead_x;                                    

Shmuel
Garnet | Level 18

Relating to your question:

       Do i have to use
%macro dt_convert (dtx , dt);
    if length(&dtx) = 4
      then &dt = mdy(01,01,input(&dtx,4.));
      else &dt = input(&dtx , mmddyy10.);
%mend dt_convert;

 

Above lines define a macro program.

I'm using it in order to reuse same code with different variables.

In this case convert character date given as mmddyy10. or as yyy only - into SAS numeric date.

The usage of this macro program is given as:

 

      %dt_convert(birth_x , birth);        /* create variable birth from birth_x */                       
      %dt_convert(dead_x , died);       /* create variable died from dead_x */      

 

Macro programs are very powerfull to save time of coding and time of debugging if you use it wisely.

There is a lot to learn about SAS macro language.

azee007
Calcite | Level 5
Dear Shmuel ,
Now i understand. I have ran teh code with changes you have suggested buy now teh log is as below with error 72 - year has many arguments

if dead= . then birthdead = put(year(born,4.),4.); /*
____
72
67 ! assigning result value when no death date = just birth YYYY */
3 The SAS System 18:58 Sunday, November 6, 2016

ERROR 72-185: The YEAR function call has too many arguments.
Shmuel
Garnet | Level 18

My fault again. Line should be:

 

if dead= . then birthdead = put(year(born),4.);

 

 

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