BookmarkSubscribeRSS Feed
🔒 This topic is solved and locked. Need further help from the community? Please sign in and ask a new question.
Solph
Pyrite | Level 9

Hi

Last week I asked a question about how to identify a list of cases present in a month between their entry date and discharge. See the code toward the end of post. I'm wondering if I can recycle the code to, now, identify a list of cases present point in time, on 5 different dates: April 1, June 30, Sept 30, Dec 31, and Mar 31. I think I can, but I can't exactly sure how to have it fixed. Any hint is appreciated.

Here is the data I have and the "want" data for fiscal year 2017-2018 (Apr-Mar) in the right columns.

*Get point in time on April 1, Jun 30, Sep 30, Dec 31, Mar 31;
data have; format entry_date discharge_date yymmdd10.; 
input id 1 @3 entry_date yymmdd10. @15 discharge_date yymmdd10. 
apr2017 jun2017 sep2017 dec2017 mar2018 apr2018 jun2018 sep2018 dec2018 mar2019
;
datalines;
1 2017-05-11  2018-08-25 0 1 1 1 1 1 1 0 0 0 
2 2017-04-01  2017-08-02 0 1 0 0 0 0 0 0 0 0
3 2018-05-11  2018-07-20 0 0 0 0 0 0 1 0 0 0
4 2016-01-05  2019-03-29 1 1 1 1 1 1 1 1 1 0 
;
quit;

 

Here is the code to identify a list of cases present in a month between their entry date and discharge.

data have; format entry_date discharge_date yymmdd10.; 
input id 1 @3 entry_date yymmdd10. @15 discharge_date yymmdd10. note $ 26-42;
datalines;
1 2017-05-11  2018-08-25 Active 2017,2018
2 2017-04-01  2017-08-02 Active 2017
3 2018-05-11  2018-07-20 Active 2018
4 2019-01-05  2019-04-29 Active 2018, 2019
5 2020-05-11  2020-05-20 Active 2020
6 2020-04-05  2020-06-02 Active 2020
;
quit;  
data want (keep=FYMO id);
    set have;
    x = intck("month", entry_date, discharge_date);
    format FYMO yymmn6.;
    do i = 0 to x;
        FYMO = intnx('month', entry_date, i, 'BEGINNING');
        output;
    end;
run;

 

1 ACCEPTED SOLUTION

Accepted Solutions
ChrisNZ
Tourmaline | Level 20

No too sure what the question is.

Like this?

do D='01apr2017'd, '01jun2017'd, '01sep2017'd, '01dec2017'd, '01mar2018'd, '01apr2018'd, '01jun2018'd, '01sep2018'd, '01dec2018'd, '01mar2019'd;
  if  ENTRY_DATE <= D <= DISCHARGE_DATE then output;
end; 

 

View solution in original post

4 REPLIES 4
ChrisNZ
Tourmaline | Level 20

No too sure what the question is.

Like this?

do D='01apr2017'd, '01jun2017'd, '01sep2017'd, '01dec2017'd, '01mar2018'd, '01apr2018'd, '01jun2018'd, '01sep2018'd, '01dec2018'd, '01mar2019'd;
  if  ENTRY_DATE <= D <= DISCHARGE_DATE then output;
end; 

 

Solph
Pyrite | Level 9

Yes, it worked and I modified a bit to suit my needs. Thank a lot.

%macro loop;
%do year=2017 %to 2019;
	data want&year;
    set have;
	if discharge_date =. or discharge_date> "&enddt"d then discharge_date="&enddt"d;
	if  ENTRY_DATE <= "01apr&year."d <= DISCHARGE_DATE then ID01apr=1;
	if  ENTRY_DATE <= "30jun&year."d <= DISCHARGE_DATE then ID30jun=1;
	if  ENTRY_DATE <= "30sep&year."d <= DISCHARGE_DATE then ID30sep=1;
	if  ENTRY_DATE <= "31dec&year."d <= DISCHARGE_DATE then ID31dec=1;
	if  ENTRY_DATE <= "31mar%eval(&year+1)"d <= DISCHARGE_DATE then ID31mar=1;
	Fyear=&year;
	output want&year;
	run;
%end;
%mend;
%loop;
data want; set want2017-want2019; run;

ChrisNZ
Tourmaline | Level 20

Why several tables? And why a macro? Would something like this work?

 

data WANT;
  set HAVE;
  do FYEAR=2017 to 2019;
    DISCHARGE_DATE = min(DISCHARGE_DATE, "&enddt"d);
    if ENTRY_DATE <= mdy( 4, 1, FYEAR)   <= DISCHARGE_DATE then ID01APR=1;
    if ENTRY_DATE <= mdy( 6, 1, FYEAR)   <= DISCHARGE_DATE then ID30JUN=1;
    if ENTRY_DATE <= mdy( 9, 1, FYEAR)   <= DISCHARGE_DATE then ID30SEP=1;
    if ENTRY_DATE <= mdy(12, 1, FYEAR)   <= DISCHARGE_DATE then ID31DEC=1;
    if ENTRY_DATE <= mdy( 3, 1, FYEAR+1) <= DISCHARGE_DATE then ID31MAR=1;
  end;
run;

 

 

ChrisNZ
Tourmaline | Level 20

Even better if you want the zeros to be populated too:

 

ID01APR = ( ENTRY_DATE <= mdy( 4, 1, FYEAR)   <= DISCHARGE_DATE ) ;

SAS Innovate 2025: Call for Content

Are you ready for the spotlight? We're accepting content ideas for SAS Innovate 2025 to be held May 6-9 in Orlando, FL. The call is open until September 25. Read more here about why you should contribute and what is in it for you!

Submit your idea!

How to Concatenate Values

Learn how use the CAT functions in SAS to join values from multiple variables into a single value.

Find more tutorials on the SAS Users YouTube channel.

Click image to register for webinarClick image to register for webinar

Classroom Training Available!

Select SAS Training centers are offering in-person courses. View upcoming courses for:

View all other training opportunities.

Discussion stats
  • 4 replies
  • 661 views
  • 0 likes
  • 2 in conversation