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swayto
Fluorite | Level 6

Data Loop;
X=0;
do Index = 1 to 5 by 2;
x=Index;
end;
run;

 

X=5 , Index=7

 

Why is index=7.

3 REPLIES 3
gamotte
Rhodochrosite | Level 12

Hello,

 

When index=5 and the interpreter meets the "end" statements, il loops back to the do

statement, increments index by 2 and compare the result to 5 => index=7>5 so the loop stops.

andreas_lds
Jade | Level 19

Adding a put statement in the loop could be helpful to understand what's happening.

Kurt_Bremser
Super User

A loop like yours is compiled to this (and the same is true for any programming language that has an iterative loop):

index = 1
start:
if index > 5 goto end
(loop code)
index + 2
goto start
end:

so you see that the index needs to go past the end value for the loop to exit.

 

 

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