BookmarkSubscribeRSS Feed
🔒 This topic is solved and locked. Need further help from the community? Please sign in and ask a new question.
Mathis1
Quartz | Level 8

Hello, 
I would like to allocate a (categorical) variable ( Y=1,2,3,4) to each observation with a precise repartition, in function of another variable (X). I explain myself :


If X=0, I want :

 - 1% of the population with Y=1

 - 10% of the population with Y=2

 - 40%   of the population with Y=3

 - 49% of the population with Y=4

And if X=1, I want : 

 - 2% of the population with Y=1

 - 12% of the population with Y=2

 - 56%   of the population with Y=3

 - 30% of the population with Y=4

Etc until X=10

I know how to make the do loop and the conditional statement :
Do X=0 to 10 ;
If X=i then ...
i=i+1;

 

But I don't know how to allocate each observation to Y in the right proportions.
Of course, I know for each X what the repartition (in percentage) should be. I just need to know how to allocate the observations to each level of Y. 

Thank you by advance for your help !

1 ACCEPTED SOLUTION

Accepted Solutions
PaigeMiller
Diamond | Level 26

Use the RAND('table', ...) function

https://documentation.sas.com/?cdcId=pgmsascdc&cdcVersion=9.4_3.5&docsetId=lefunctionsref&docsetTarg...

 

Example:

if x=1 then y=rand('table',0.01,0.1,0.4,0.49);
--
Paige Miller

View solution in original post

3 REPLIES 3
PeterClemmensen
Tourmaline | Level 20

How many different values can X have? 

 

Also, can you provide some sample data and what your desired result looks like? Makes it much easier to provide usable code.

PaigeMiller
Diamond | Level 26

Use the RAND('table', ...) function

https://documentation.sas.com/?cdcId=pgmsascdc&cdcVersion=9.4_3.5&docsetId=lefunctionsref&docsetTarg...

 

Example:

if x=1 then y=rand('table',0.01,0.1,0.4,0.49);
--
Paige Miller
ballardw
Super User

Exactly how many observations are you going to process?

 

If you only have 25 records where X=1 it is going to be very hard to get any distribution that "exactly matches" the stated percentages. (1 value of y=1 is 4% in this case). Other similar issues will exist with other numbers of records with any given X value.

 

So what would expect for a "distribution" if you only have 25 X=1 records? or 50 X=0 (1% = half a record or Y=1 is 2%).

 

It is unlikely to be able to match any "exact distribution" if the number of X= records is not exactly 100 or a multiple of 100. Also and "exact distribution" likely is not going to be a true random distribution if that is what is desired.

How to Concatenate Values

Learn how use the CAT functions in SAS to join values from multiple variables into a single value.

Find more tutorials on the SAS Users YouTube channel.

SAS Training: Just a Click Away

 Ready to level-up your skills? Choose your own adventure.

Browse our catalog!

Discussion stats
  • 3 replies
  • 1085 views
  • 0 likes
  • 4 in conversation