Determining date difference

[kamlesh_suthar]

Hi,

want to code the following

assume i have a data set which contains time series date, product id and launch date if the difference between the launch date and date is more than 6 month, we should consider the history of that product and take all records for analysis, else ignore the product.

Product id	date	launch date
1	201710	201710
1	201711	201710
1	201712	201710
1	201801	201710
1	201802	201710
2	201710	201706
2	201711	201706
2	201712	201706
2	201801	201706
2	201802	201706

In the above since product 1 was launched in 201710, and it is not 6 month old, we should ignore the history of this product, while product 2 is already 6 month old now hence we should consider this product.

Thanks in advance

[PaigeMiller]

You can use the INTCK function, something like this

data want;
    set have;
    if intck(launchdate,date)>6 then output;
run;

[Kurt_Bremser]

You posted this question in the "Base SAS Programming" community. Do you think that "base sas" (sic) is a descriptive subject (what you were asked for when hitting the submit button)?

Please be a little more creative next time around.

I will edit the subject of your initial post and the answers.

[RW9]

Not tested, post test data in the form of a datastep!

proc sql;
  create table want as
  select *
  from   have
  where product_id in (select distinct product_id from have where intck('year',launch_date,date) <=6);
quit;

[PGStats]

Convert the dates to SAS dates and use function intck to calculate the number of months:

data have;
input Product _date _ldate;
date = mdy(mod(_date,100),1,floor(_date/100));
ldate = mdy(mod(_ldate,100),1,floor(_ldate/100));
drop _: ;
format date ldate yymmdd10.;
datalines; 
1 201710 201710 
1 201711 201710 
1 201712 201710 
1 201801 201710 
1 201802 201710 
2 201710 201706 
2 201711 201706 
2 201712 201706 
2 201801 201706 
2 201802 201706 
;

proc sql;
create table want as
select
    product,
    date,
    ldate
from
    have
group by product
having intck("month",min(ldate), max(date), "continuous") > 6;
select * from want;
quit;

[Rick_SAS]

To build on PGStats' response, the article 

"INTCK and INTNX: Two essential functions for computing intervals between dates in SAS"

contains more information, discussion, and an example of using the INTCK function and the 'CONTINUOUS' option.