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lulu3
Obsidian | Level 7

Hi Everyone, I would like to delete the information if the patient take >=1 drugs in the same day.  Bascially, if the patient take two or drugs in the same day, then delete all the information from this date.

orginal data:

ID

Date

Drug

101

10/1/2019

A

101

10/1/2019

B

101

10/1/2019

C

101

10/2/2019

A

101

10/3/2019

A

101

10/3/2019

B

101

10/3/2019

B

 

I want:

ID

Date

Drug

101

10/2/2019

A

 

Thanks for your help,

Sarah

1 ACCEPTED SOLUTION

Accepted Solutions
s_lassen
Meteorite | Level 14

Assuming your input is sorted by ID and DATE (if not, PROC SORT it):

data want;
  set have;
  by ID Date;
  if first.date and last.date;
run;

 

View solution in original post

5 REPLIES 5
mklangley
Lapis Lazuli | Level 10

Here's one way to do it:

data have;
    input ID Date: mmddyy10. Drug $;
    format Date mmddyy10.;
    datalines;
    101 10/1/2019 A
    101 10/1/2019 B
    101 10/1/2019 C
    101 10/2/2019 A
    101 10/3/2019 A
    101 10/3/2019 B
    101 10/3/2019 B 
    ;
run;

/* Find which dates have only one drug */
proc sql;
    create table date_count as
    select date, count(distinct drug) as count
    from have
    group by date
    having count(distinct drug) = 1;
quit;

/* Select only those dates from the original data */
proc sql;
    create table want as
    select a.id, a.date, a.drug
    from have a
    inner join date_count b 
        on a.date = b.date;
quit;
Kurt_Bremser
Super User

Since SAS allows a remerge, you can do it in one select:

proc sql;
create table want as
  select *
  from have a
  group by id, date
  having count(distinct drug) = 1  
;
quit;
Jagadishkatam
Amethyst | Level 16

please try this untested code

 

proc sql;
create table want as select *, count(id) as cnt from have group by id, date having cnt<=1;
quit;
Thanks,
Jag
novinosrin
Tourmaline | Level 20

Hi @lulu3  A sorted dataset (as your sample suggests) may benefit from a one pass

 


data have;
    input ID Date: mmddyy10. Drug $;
    format Date mmddyy10.;
    datalines;
    101 10/1/2019 A
    101 10/1/2019 B
    101 10/1/2019 C
    101 10/2/2019 A
    101 10/3/2019 A
    101 10/3/2019 B
    101 10/3/2019 B 
    ;
run;

data want;
 do _n_=1 by 1 until(last.date);
  do until(last.drug);
   set have;
   by id date drug;
  end;
 end;
 if _n_=1 then output;
run;
s_lassen
Meteorite | Level 14

Assuming your input is sorted by ID and DATE (if not, PROC SORT it):

data want;
  set have;
  by ID Date;
  if first.date and last.date;
run;

 

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