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RRzio11
Calcite | Level 5

Hello,

 

I am needing to convert the "DATEINT" variable into a numeric, date format (mmddyy10.) however I am having trouble doing so. 

 

DATA WAVE5_8LD;
SET WAVE5_8L;
NDATEINT= INPUT(DATEINT,DDMMYY10.);
FORMAT DATEINT MMDDYY10.;
RUN;

 

I want to be able to format "DATEINT"  to match how variable "dod" is so that I can perform an analysis on them. This is from a pre-existing dataset. 

 

 

Screen Shot 2020-08-11 at 12.09.25 AM.pngScreen Shot 2020-08-11 at 12.09.39 AM.pngScreen Shot 2020-08-11 at 12.09.32 AM.png

6 REPLIES 6
andreas_lds
Jade | Level 19

It seems that you are using the wrong informat, ddmmyy requires the month to be a number from 1 to 12, not the abbreviated month name. Unfortunately you have not posted the data in usable form, so i won't provide code. Maybe reading those dates is possible with date9-informat after applying compress-function to dateint removing the hyphens.

RRzio11
Calcite | Level 5

attached is my dataset

Kurt_Bremser
Super User

Read like this:

data test;
infile '/folders/myfolders/WAVE5_8L.csv' dlm=',' dsd firstobs=2;
input
  q_no $
  isdead
  agedie
  dod :mmddyy10.
  YSMOKE
  wave
  DATEINT :date11.
  UM
  UG
  TOTMMSE
  TOTADL
  sfrailcatb
  sex
  nfrac
  marstat
  ll
  lcancr
  khyper
  jstrok
  icardi
  cesdtot
  bmi
  age
  mdiab
;
format dod dateint yymmdd10.;
run;
RRzio11
Calcite | Level 5
Thank you so much! could you help me calculate the difference between "Dateint" and "DOD" in days?

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