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BochengJing
Fluorite | Level 6

Hello SAS users, I am working on a longitudinal study data where I need to code missing value indicator for an outcome. So for each person ID, the outcome was measured several times throughout different time point. If the outcome is not missing, we say the outcome is observed (Indicator="O"), if some of the outcomes are missing but later the outcome appeared within the same person ID, then we say the outcome is intermittently missing (Indicator="I"). If the outcomes are missing at one point till the end of the person ID, we say this person is dropout (Indicator="D"). Here is how the data looks like: 

IDTimeOutcomeIndicator
132O
16.I
193O
1121O
115.I
1181O
232O
263O
29.I
212.I
2153O
2182O
331O
361O
39.D
312.D
315.D
318.D
433O
46.I
492O
412.D
415.D
418.D

 

Would you mind helping me figure a way to code the indicator variable that contains "observed", "Intermittently missing", "Dropout"? The original data only has ID, time, and outcome; I added the indicator variable for the demonstration. 

 

Thank you.

1 ACCEPTED SOLUTION

Accepted Solutions
ChrisNZ
Tourmaline | Level 20

Like this?

data HAVE;
  input ID TIME OUTCOME ;
cards;
1 3 2 O
1 6 . I
1 9 3 O
1 12 1 O
1 15 . I
1 18 1 O
2 3 2 O
2 6 3 O
2 9 . I
2 12 . I
2 15 3 O
2 18 2 O
3 3 1 O
3 6 1 O
3 9 . D
3 12 . D
3 15 . D
3 18 . D
4 3 3 O
4 6 . I
4 9 2 O
4 12 . D
4 15 . D
4 18 . D
run;

proc sql nothreads;
  create table LASTOUTCOME as 
  select ID, max(N*(OUTCOME>0)) as LASTOUTCOME  
  from (select *, monotonic() as N from HAVE) 
  group by ID 
  order by ID ;
quit;

data WANT;
  merge HAVE LASTOUTCOME;
  by ID;
  length INDICATOR $1;
  INDICATOR=ifc(OUTCOME,'O', ifc(_N_<=LASTOUTCOME ,'I', 'D' ));
run;
ID TIME OUTCOME LASTOUTCOME INDICATOR
1 3 2 6 O
1 6 . 6 I
1 9 3 6 O
1 12 1 6 O
1 15 . 6 I
1 18 1 6 O
2 3 2 12 O
2 6 3 12 O
2 9 . 12 I
2 12 . 12 I
2 15 3 12 O
2 18 2 12 O
3 3 1 14 O
3 6 1 14 O
3 9 . 14 D
3 12 . 14 D
3 15 . 14 D
3 18 . 14 D
4 3 3 21 O
4 6 . 21 I
4 9 2 21 O
4 12 . 21 D
4 15 . 21 D
4 18 . 21 D

 

View solution in original post

2 REPLIES 2
mkeintz
PROC Star

Read all records for each ID twice:

  1. First pass determine which record number is the last non-missing record, call it last_observed.
  2. Second pass
    1. if the record-in-hand is after last_observed, then you have a 'D'
    2. all other missing are 'I'
    3. all non-missings are 'O'
    4. then output the record.

This is untested, in the absence of a working DATA step with sample data.

 

data want (drop=i last_observed);
  do i=1 by 1 until (last.id);
    set have;
    by id;
    if outcome^=. then last_observed=i;
  end;

  do i=1 by 1 until (last.id);
    if      i>last_observed  then indicator='D'; 
    else if missing(outcome) then indicator='I';
    else                          indicator='O';
    output;
  end;
run;
--------------------------
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--------------------------
ChrisNZ
Tourmaline | Level 20

Like this?

data HAVE;
  input ID TIME OUTCOME ;
cards;
1 3 2 O
1 6 . I
1 9 3 O
1 12 1 O
1 15 . I
1 18 1 O
2 3 2 O
2 6 3 O
2 9 . I
2 12 . I
2 15 3 O
2 18 2 O
3 3 1 O
3 6 1 O
3 9 . D
3 12 . D
3 15 . D
3 18 . D
4 3 3 O
4 6 . I
4 9 2 O
4 12 . D
4 15 . D
4 18 . D
run;

proc sql nothreads;
  create table LASTOUTCOME as 
  select ID, max(N*(OUTCOME>0)) as LASTOUTCOME  
  from (select *, monotonic() as N from HAVE) 
  group by ID 
  order by ID ;
quit;

data WANT;
  merge HAVE LASTOUTCOME;
  by ID;
  length INDICATOR $1;
  INDICATOR=ifc(OUTCOME,'O', ifc(_N_<=LASTOUTCOME ,'I', 'D' ));
run;
ID TIME OUTCOME LASTOUTCOME INDICATOR
1 3 2 6 O
1 6 . 6 I
1 9 3 6 O
1 12 1 6 O
1 15 . 6 I
1 18 1 6 O
2 3 2 12 O
2 6 3 12 O
2 9 . 12 I
2 12 . 12 I
2 15 3 12 O
2 18 2 12 O
3 3 1 14 O
3 6 1 14 O
3 9 . 14 D
3 12 . 14 D
3 15 . 14 D
3 18 . 14 D
4 3 3 21 O
4 6 . 21 I
4 9 2 21 O
4 12 . 21 D
4 15 . 21 D
4 18 . 21 D

 

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