I am attempting to write a program that will assign items a location in 5 row by 5 column boxes. The number of items will vary by the shipment, and I want the program to be able to adapt to whatever that total number of items is.
Using the code below, I have been successful at assigning the proper number of boxes I will need (25 item per box, counting up the number of boxes until all items have a box assigned) however, I am having trouble with the rows and columns. Once a new box starts and the number of respective rows and columns hit 5, I need the values to start back at 1 again for the new box. What I have below just continues the numbering to 6, 7, 8, etc.
data shipping_location;
set manifest;
shipping_box = .;
shipping_row = .;
shipping_col = .;
do b = 1 to _n_;
if shipping_box = . then do;
if _n_ =< 81*b then shipping_box = b;
do r = 1 to _n_;
if shipping_row = . then do;
if _n_ =< 9*r then shipping_row = r;
do c = 1 to _n_;
if shipping_col = . then do;
if _n_ =< c then shipping_col = c;
end;
end;
end;
end;
end;
end;
run;
I want the output to look like this:
Item | Box | Row | Col |
A | 1 | 1 | 1 |
B | 1 | 1 | 2 |
C | 1 | 1 | 3 |
D | 1 | 1 | 4 |
E | 1 | 1 | 5 |
F | 1 | 2 | 1 |
G | 1 | 2 | 2 |
H | 1 | 2 | 3 |
I | 1 | 2 | 4 |
J | 1 | 2 | 5 |
K | 1 | 3 | 1 |
L | 1 | 3 | 2 |
M | 1 | 3 | 3 |
N | 1 | 3 | 4 |
O | 1 | 3 | 5 |
P | 1 | 4 | 1 |
Q | 1 | 4 | 2 |
R | 1 | 4 | 3 |
S | 1 | 4 | 4 |
T | 1 | 4 | 5 |
U | 1 | 5 | 1 |
V | 1 | 5 | 2 |
W | 1 | 5 | 3 |
X | 1 | 5 | 4 |
Y | 1 | 5 | 5 |
Z | 2 | 1 | 1 |
AA | 2 | 1 | 2 |
BB | 2 | 1 | 3 |
CC | 2 | 1 | 4 |
DD | 2 | 1 | 5 |
EE | 2 | 2 | 1 |
FF | 2 | 2 | 2 |
GG | 2 | 2 | 3 |
HH | 2 | 2 | 4 |
II | 2 | 2 | 5 |
Thank you!
Please see how close this comes
data want; set have; col = mod(_n_-1,5)+1; row = mod((floor((_n_-1)/5)+1)-1,5)+1; box = mod( floor((_n_-1)/25 +1),25); run;
Please see how close this comes
data want; set have; col = mod(_n_-1,5)+1; row = mod((floor((_n_-1)/5)+1)-1,5)+1; box = mod( floor((_n_-1)/25 +1),25); run;
Simple arithmetic:
data want ;
set have ;
box = ceil (_n_ / 25) ;
row = ceil (_n_ / 5) ;
col = 1 + mod (_n_ - 1, 5) ;
run ;
Kind regards
Paul D.
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