how to achieve the desired result

[Ravikumarkummari]

Hi all,

empid	salary
1	15000
2	20000
3	30000
4	45000
5	60000
6	70000
7	10000
8	20000
9	100000
10	35000
11	40000
12	7000
13	90000
14	80000
15	70000
16	65000
17	87000
18	56000
19	8000
20	7000
21	12000
22	19000
23	23000
24	34000
25	46000
26	58000
27	67000
28	78000
29	5000
30	84000

having the data like above.
empid and salary information is available in pdf.
min salary is 5000 and maximum is 100000.
i want the output like devide this salaries into 5 group.
each group contain 20000 salaries. i.e.

sal_group                              count(employees)

1st group 0-20000               number of employees in that each group.
2nd group 20000-40000       number of employees in that each group.
last group
80000-100000                     number of employees in that each group.

thanks in advance.

[KachiM]

I think a simple division of Salary will do the trick. No Proc is needed. You need an array to hold the counts.

data want;

array k[5] _temporary_;

   set have end = eof;

   i = ceil(salary / 20000);

   k + 1;

   if eof then

      do i = 1 to dim(k);

         group = i;

         low_value = (i - 1) * 20000;

         high_value = i * 20000;

         count = k;

         output;

      end;

keep group low_value high_value count;

run;

[Ksharp · Accepted solution]

data have;

input empid salary ;

cards;

1 15000

2 20000

3 30000

4 45000

5 60000

6 70000

7 10000

8 20000

9 100000

10 35000

11 40000

12 7000

13 90000

14 80000

15 70000

16 65000

17 87000

18 56000

19 8000

20 7000

21 12000

22 19000

23 23000

24 34000

25 46000

26 58000

27 67000

28 78000

29 5000

30 84000

;

run;

proc format;

value fmt

0-20000='1'

20000<-40000='2'

40000<-60000='3'

60000<-80000='4'

80000<-100000='5';

run;

data want;

set have;

group=put(salary,fmt.);

run;

[Ravikumarkummari]

Thanks a lot xia keshan sir

[Ksharp]

data have;

input empid salary ;

cards;

1 15000

2 20000

3 30000

4 45000

5 60000

6 70000

7 10000

8 20000

9 100000

10 35000

11 40000

12 7000

13 90000

14 80000

15 70000

16 65000

17 87000

18 56000

19 8000

20 7000

21 12000

22 19000

23 23000

24 34000

25 46000

26 58000

27 67000

28 78000

29 5000

30 84000

;

run;

proc format;

value fmt

0-20000='1'

20000<-40000='2'

40000<-60000='3'

60000<-80000='4'

80000<-100000='5';

run;

data want;

set have;

group=put(salary,fmt.);

run;