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tish
Calcite | Level 5

Yes. Look at the top of the code for the table add_month. Instead of defining month as "int(day / 30) + 1 as month" substitute

     case
           when day <= 30 then 1
           when day <= 60 then 2
           else .
        end as month 

You will need to expand this out to set the boundaries, but pregnancies last only 10 months at the most... Smiley Happy Remember to use a comma at the end if you will continue with another variable definition.

Hope this helps.

Dorota_Jarosz
Obsidian | Level 7

Andp: Yes, you are right. I am sorry.

The function mod(Days,30) should be replaced by int(Days/30), so the data step have2 becomes:

data have2;

format id 8. Days best4.;

set have;

month=int(Days/30)+1;

if int(Days/30)=0 then Monthval1=Value;

else if int(Days/30)=1 then Monthval2=Value;

else if int(Days/30)=2 then Monthval3=Value;

else if int(Days/30)=3 then Monthval4=Value;

else if int(Days/30)=4 then Monthval5=Value;

run;

I added the month variable so it is easier to validate.

Good luck,

Dorota

Dorota_Jarosz
Obsidian | Level 7

For completeness I include the entire code now, together with the generated values for 10 IDs.

data have;
do Days=1 to 300;
do id=1 to 10;
Value=int(30*ranuni(1)/1);
output;
end;
end;
run;

data have2;
format id 8. Days best4.;
set have;
month=int(Days/30)+1;
if Days<=30 then month=1;
else if Days<=60 then month=2;
else if Days<=90 then month=3;
else if Days<=120 then month=4;
else if Days<=150 then month=5;
else if Days<=180 then month=6;
else if Days<=210 then month=7;
else if Days<=240 then month=8;
else if Days<=270 then month=9;
else if Days<=300 then month=10;
else month=11; *just in case *;
if month=1 then Monthval1=Value;
else if month=2 then Monthval2=Value;
else if month=3 then Monthval3=Value;
else if month=4 then Monthval4=Value;
else if month=5 then Monthval5=Value;
else if month=6 then Monthval6=Value;
else if month=7 then Monthval7=Value;
else if month=8 then Monthval8=Value;
else if month=9 then Monthval9=Value;
else if month=10 then Monthval10=Value;
else Monthval11=Value;
run;

proc sort data=have2;
by id days;
run;


%let months=Monthval1 Monthval2 Monthval3 Monthval4 Monthval5
     Monthval6 Monthval7 Monthval8 Monthval9 Monthval10;
%let sum_months=sum_Monthval1 sum_Monthval2 sum_Monthval3 sum_Monthval4 sum_Monthval5
     sum_Monthval6 sum_Monthval7 sum_Monthval8 sum_Monthval9 sum_Monthval10;
%let avg_months=avg_Monthval1 avg_Monthval2 avg_Monthval3 avg_Monthval4 avg_Monthval5
                avg_Monthval6 avg_Monthval7 avg_Monthval8 avg_Monthval9 avg_Monthval10;

proc summary data=have2  ;
var Monthval1 -- Monthval10;
by id;
output out=monthly_stats (drop=_FREQ_ _TYPE_)
  sum=&sum_months mean=&avg_months;
run;
data want;
format id best4. sum_Monthval1 best8. avg_Monthval1 8.2
sum_Monthval2 best8. avg_Monthval2 8.2
sum_Monthval3 best8. avg_Monthval3 8.2
sum_Monthval4 best8. avg_Monthval4 8.2
sum_Monthval5 best8. avg_Monthval5 8.2
sum_Monthval6 best8. avg_Monthval6 8.2
sum_Monthval7 best8. avg_Monthval7 8.2
sum_Monthval8 best8. avg_Monthval8 8.2
sum_Monthval9 best8. avg_Monthval9 8.2
sum_Monthval10 best8. avg_Monthval10 8.2;
set monthly_stats;
run;

options nocenter nodate;
proc print data=want uniform noobs;
run;

andp
Calcite | Level 5

Hi Dorota and tish,

After merging your two codes together I got it to work with my being able to change the length of each month period. The final result looks exactly how I pictured it! (I just have to create code for the trimesters but that shouldn't be too hard from here on out) Thanks again for all your help!

Reeza
Super User

Why not use proc means with a format?

proc format;

     value days_fmt

     0 - 30 = '<30'

      31 - 60 = '31 to 60'

      61 - 90 = '61 to 90';

run;

proc means data=have;

class id days;

format days days_fmt.;

var value;

output out=output sum= mean=/autoname;

run;

And then transpose the answer at the end if you need to, but this way you don't need to hardcode anything, ie month1, month....

tish
Calcite | Level 5

Now I understand what you want. Define month as int(day / 30) + 1 and trimester as int(day / 90) + 1. I have tested the following and it works:

proc sql;

   create table add_month as

      select

         id,

         start_date,

         end_date,

         day,

         value,

         int(day / 30) + 1 as month,

         int(day / 90) + 1 as trimester

      from

         original_data;

     

   create table monthly_values as

      select

         id,

         month,

         "Month" || put(month, z2.0) || "Sum" as sum_ID,

         "Month" || put(month, z2.0) || "Avg" as avg_ID,

         sum(value) as sum_value,

         avg(value) as avg_value

      from

         have

      group by

         id,

         month

      order by

         id,

         month;

quit;

proc transpose data=monthly_values out=sum_value (drop=_name_);

   id sum_ID;

   var sum_value;

   by id;

run;

proc transpose data=monthly_values out=avg_value (drop=_name_);

   id avg_ID;

   var avg_value;

   by id;

run;

data summary_data;

   merge sum_value avg_value;

   by id;

run;

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