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JackFerral
Calcite | Level 5

error

1 ACCEPTED SOLUTION

Accepted Solutions
stat_sas
Ammonite | Level 13

Something like this will produce the desired output. I am assuming the difference between dates as number of days.

data have;

input m d y date1 :mmddyy10.;

date2=mdy(m,d,y);

date_diff_day=intck('day',date2,date1);

format date1 date2 date9.;

datalines;

1     20     1985  01/30/1986

;

proc print data=have;

run;

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2 REPLIES 2
stat_sas
Ammonite | Level 13

Something like this will produce the desired output. I am assuming the difference between dates as number of days.

data have;

input m d y date1 :mmddyy10.;

date2=mdy(m,d,y);

date_diff_day=intck('day',date2,date1);

format date1 date2 date9.;

datalines;

1     20     1985  01/30/1986

;

proc print data=have;

run;

dkb
Quartz | Level 8 dkb
Quartz | Level 8

As the original question has been deleted, here is a copy from Google's cache.

------------------------------------------------------------------------------------------------------------------

I have a Data set that contains separate columns for day, month and year. I need to consolidated these into one single variable .

Example:

1     20     1985   (consolidated into a single SAS date)

Would I want to use the MDY Function? and what would this look like?

Once I've consolidated this date I need to find the difference from this new column and another date column that was originally a single columned date.

Thanks!

Jack

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