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BETO
Fluorite | Level 6

HI

i have a table that has duplicate entries here is and example.

ID.      Lat.       Long

001.    0             0

001.    33.4.      -112.221

i would want to remove the duplicate that has 0 for lat and long and keep the entry  where there is a lat and long.

here is  a snippet of what I'm using

proc sort data= table1

out=table1

nodupkey;

where lat <> 0;

by  ID;

which works except it also removes some id  that's are not dups  but have a 0 in the lat and long columns ....thanks again for assistance

1 ACCEPTED SOLUTION

Accepted Solutions
Reeza
Super User

Sort first descending by lat then use nodupkey. This will push the observations with values before the ones with 0.

proc sort data=have; by id descending lat;

run;

proc sort data=have nodupkey; by id;

run;

View solution in original post

4 REPLIES 4
Reeza
Super User

Sort first descending by lat then use nodupkey. This will push the observations with values before the ones with 0.

proc sort data=have; by id descending lat;

run;

proc sort data=have nodupkey; by id;

run;

Astounding
PROC Star

The possibility of negative values can make this tricky.  If you can guarantee that each ID has at most one record with all 0s, here's a way to do it:

proc sort data=have;

   by id;

run;

data want;

   merge have (where=(lat=0 and long=0))

             have (where=(lat ne 0 or long ne 0));

   by id;

run;

Good luck.

Reeza
Super User

True, but latitude and longitude have very well defined transition points to negative/positive. If I'm dealing with Canadian data for example, I know that all my latitudes will be positive.

For countries that cross boundaries another solution would be required.

Ksharp
Super User

How about this:

data have;
input ID   $   Lat       Long ;
cards;
001.    0             0
001.    33.4      -112.221
002.     0             0
;
run;
proc sort data=have;
   by id;
run;
data want;
 set have;
 by id;
 if  lat = 0 and not(first.id and last.id) then delete;
run;

Ksharp

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