I need to convert a character column to the date format
The format I am looking for is 05/04/1995
Here are my sas code:
data degree;
set prod.shrdgmr;
grad_term=input(substr(SHRDGMR_GRAD_DATE, 1,10), mmddyy10.);
keep shrdgmr_pidm SHRDGMR_GRAD_DATE grad_term;
where shrdgmr_pidm=14921;
run;
but the output for created column grad_term is blank
Any idea how I should change the code? Thanks!!
@xliu1 wrote:
I need to convert a character column to the date format
The format I am looking for is 05/04/1995
Here are my sas code:
data degree; set prod.shrdgmr; grad_term=input(substr(SHRDGMR_GRAD_DATE, 1,10), mmddyy10.); keep shrdgmr_pidm SHRDGMR_GRAD_DATE grad_term; where shrdgmr_pidm=14921; run;
but the output for created column grad_term is blank
Any idea how I should change the code? Thanks!!
Why are you attempting to read a date that starts with the year using an Informat that starts with month????
Did you read the log with all the invalid data messages??
Try
grad_term=input(SHRDGMR_GRAD_DATE,yymmdd10.); format gradterm mmddyy10.;
The Informat length of 10 says to only read the first 10 characters so the substr isn't needed. The correct Informat is.
@xliu1 wrote:
I need to convert a character column to the date format
The format I am looking for is 05/04/1995
Here are my sas code:
data degree; set prod.shrdgmr; grad_term=input(substr(SHRDGMR_GRAD_DATE, 1,10), mmddyy10.); keep shrdgmr_pidm SHRDGMR_GRAD_DATE grad_term; where shrdgmr_pidm=14921; run;
but the output for created column grad_term is blank
Any idea how I should change the code? Thanks!!
Why are you attempting to read a date that starts with the year using an Informat that starts with month????
Did you read the log with all the invalid data messages??
Try
grad_term=input(SHRDGMR_GRAD_DATE,yymmdd10.); format gradterm mmddyy10.;
The Informat length of 10 says to only read the first 10 characters so the substr isn't needed. The correct Informat is.
Thanks for your response. This works out.
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