I have code1=146
what is the meaning of "&&code&j
when j=1 in a loop
How do I resolve it???
Thanks
With a loop SAS is looking for a series of macro variables &code1 &code2 &code3. The starting && tells SAS that something has to resolve first before looking for the actual value of the variable. So & &code&j => &code1 .
And in your example when j=1 &&code&j should have a value of 146.
If you want to see the value:
%put &&code&j; shows the value in the log.
&&code&j first resolve to &code1, then &code1 resolve to 146.
With a loop SAS is looking for a series of macro variables &code1 &code2 &code3. The starting && tells SAS that something has to resolve first before looking for the actual value of the variable. So & &code&j => &code1 .
And in your example when j=1 &&code&j should have a value of 146.
If you want to see the value:
%put &&code&j; shows the value in the log.
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