Generate variable that shows three or more of the questions are missing.

[Sofia2022]

Hi
 
We currently have 2 surveys (Survey_One and Survey_two). Survey_one contains 11 questions (item 1 to 11) and survey_two contains 10 questions (item 1 to 10).  I want to create a variable that indicate a survey is considered complete if 9 of 11 questions are not missing for survey_one and if 8 of 10 questions for suverve_two are not missing.  (Variable name e.g: complete (1=yes, 0=no)).
 
For example,
person_ID=1 completed Survey_one and item1 to item3 are missing and so complete=0
person_ID=2 completed Survey_one and none of the questions/items are missing and so complete=1
 
Below is a sample of the data.
person_ID item1 item2 item3 item4 item5 item6 item7 item8 item9 item10 item11 Survey_number
1 . . . 2 2 3 3 3 2 0 0 Survey_One
2 1 3 0 0 4 1 4 3 4 3 3 Survey_One
3 0 0 0 0 0 0 2 2 0 0 0 Survey_One
4 1 2 1 1 1 1 3 3 2 1 1 Survey_One
5 1 0 0 0 0 0 0 1 2 0 . Survey_two
6 0 0 0 0 0 0 0 0 1 0 . Survey_two
7 0 2 0 0 0 0 3 3 1 0 . Survey_two
8 0 0 0 . 0 . 1 . 1 1 . Survey_two
9 0 1 0 0 0 0 1 0 0 0 . Survey_two
10 1 3 3 0 2 . . 0 2 3 . Survey_two
11 2 0 4 0 0 3 1 2 0 0 . Survey_two
 
Thanks

[andreas_lds]

Following your description id=1 must have complete = 1 because 8 item-variables are non-missing.

[Sofia2022]

Apologies there was an error in my post which I corrected now. ID=1 completed survey_one that contains 11 questions item1 to item11, where 3 of the items are missing and so complete=0.

[PaigeMiller]

UNTESTED CODE

data want;
    set have;
    if survey_number="Survey_One" then complete=nmiss(of item1-item11)<=2;
    else if survey_number='Survey_Two' then complete=nmiss(of item1-item10)<=2;
run;

If you want tested code, please provide data as working SAS data step code.