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Salah
Quartz | Level 8

Hello Rick,

 

You helped me earlier to solve the problem of having negative argument inside the log function..... I was happy about to the point that I forgot that I need to carry matrix operations and this won't work due to missing values.

 

My question is: Can I just replace the missing values in 

f = j(nrow(x), ncol(x), .); /* initialize return values to missing */


by any other small value? something like 0.01........BUT if I do so won't I be off ? Is there away that I can maybe delete the missing values well I may end up of a smaller vector than the actual size but I believe that I don't have many missing values!

 

Thank you,

Salah


Proc iml;

seed1=12345;
seed2=678;
seed=0;

m=10;K=1000;


a1=4; a2=5.5;

z= 1; 


mu=3;lambda=2 ;  *Initial values for S;

C=10;
********************** Initial values for r and S for the Bayes case *************************;

Prior_a1=J(10000,1,0);	Prior_a2=J(10000,1,0);prior_g=J(10000,1,0);
Do I=1 to 10000;
	 Prior_a1[i]=rangam(seed,a1);
	 Prior_a2[i]=rangam(seed,a2);
	 prior_g[i]=Prior_a1[i]/(Prior_a1[i]+Prior_a2[i]);
end; 			*DO LOOP OF THE GAMMA;
alpha1=Prior_a1[:]; *true value for alpha1;
alpha2=Prior_a2[:];	*true value for alpha2;


gamma=alpha1/(alpha1+alpha2);

*gamma= prior_g[:];

***********************************************************************;
*************************************************************;
*** 					LOG likelihood 
*************************************************************;
start LogLik(param) global (m,X,Y);

		
    f=0;
    alpha1=param[1];
    alpha2=param[2];
	c=param[3];
       
	 
	 
	 sum=log(1+alpha1*X+alpha2*Y) ;

     f=f+m*log( alpha1*alpha2*c*(1+c) )-(c+2)*sum[+];

     return(f);
     finish;

**************************************************************;
/* Trap bad domain values for the Linex; return missing values when x outside domain */

start Func1(x);
   f = j(nrow(x), ncol(x), .);    /* initialize return values to missing */
   /* trap bad domain values */

   d1 = x;

   domainIdx = loc( d1>0 );     /* find values inside domain */
   if ncol(domainIdx)=0 then return(f); /* all inputs invalid; return missing */
 
   t = x[domainIdx];              /* elements of t are valid */
   numer = log(t);

   f[domainIdx] = numer;  /* evaluate f(t) */
   return( f );
finish;


******************************************************************;

C_MLE=J(k,1,0); gamma_mle=J(k,1,0);S_mle=J(k,1,0);
  gamma_Lin=J(k,1,0);  gamma_pre=J(k,1,0);

X=J(m,1,0);Y=J(m,1,0);

Do N1=1 to K;


** Data simulation using this procedure ;

*Start Data(m,c,alpha1,alphau2,X,Y) global(seed1, seed2);

U1=J(m,1,0);U2=J(m,1,0);

do i=1 to m;
	U1[i]=Uniform(seed1);
	U2[i]=Uniform(seed2);

	X[i]=( (1-U1[i])**(-1/c) -1 )/alpha1;*simulation is written differently;
	
	Y[i]=(1+alpha1*X[i])/alpha2*( (1-U2[i])**(-1/(1+c)) -1   );

end;


**************************************************************************************;

***************  Optimization Step to find MLEs *********************;

************* Constrain***********************;

    con={1.e-6 1.e-6 1.e-6, . . .};
    opt={1};  
    *x0={0,0,0};
	x0=alpha1||alpha2||c; *initial guess done by SAS;

	tc={10000 15000};

***************  NLPQN for the Lomax function *********************;

call  NLPNRA(rc, param_ret, "LogLik", x0, opt, con,tc);

alpha1_mle=param_ret[1];
alpha2_mle=param_ret[2];
c_mle[N1]=param_ret[3];


Gamma_mle[N1]=alpha1_mle/(alpha1_mle+alpha2_mle);
S_mle[N1]=(alpha1_mle+alpha2_mle);




**********************************************************************;


************************************************************************************;
*************     Derivations For Lindleys method             **********************;
************************************************************************************;

**L_ggg: derivative w.r.t gamma-gamma-gamma ;
**L_ggs: derivative w.r.t. gamma-gamma-S;

sum_ggg=(   S_mle[N1]#(X-Y)/( 1+gamma_MLE[N1]#S_MLE[N1]#(X-Y)+S_MLE[N1]#Y )    )##3;

L_ggg=-2*m/(1-gamma_mle[N1])**3 +  2*m/gamma_mle[N1]**3 -2*(2+c_mle[N1])* sum_ggg[+];

*********************************************************************************************************; 
 
sum_ggs1=( 2# S_mle[N1]**2#(X-Y)##2#(gamma_mle[N1]#(X-Y)+Y ))/( 1+gamma_MLE[N1]#S_MLE[N1]#(X-Y)+S_MLE[N1]#Y ) ##3 ;
sum_ggs2=( 2# S_mle[N1]#(X-Y)##2/( 1+gamma_MLE[N1]#S_MLE[N1]#(X-Y)+S_MLE[N1]#Y )    )##2;

L_ggs= -(2+c_mle[N1]) *(sum_ggs1[+]-sum_ggs2[+])   ;

 **********************************************************************************************************;
* L_gss was missing here  ;

sum_gss1= 2# S_mle[N1]#(X-Y)#( gamma_mle[N1]#(X-Y)+Y )##2 /( 1+gamma_MLE[N1]#S_MLE[N1]#(X-Y)+S_MLE[N1]#Y ) ##3 ;
sum_gss2=2# (X-Y) #( gamma_MLE[N1]#(X-Y)+Y )/( 1+ gamma_MLE[N1]#S_MLE[N1]#(X-Y)+S_MLE[N1]#Y     )##2;

L_gss= -(2+c)*( sum_gss1[+] - sum_gss2[+]  );
 
**************************************************************************************************;
**************************************************************************************************;
sum_sss=( (gamma_mle[N1]#(X-Y)+Y )/( 1+gamma_MLE[N1]#S_MLE[N1]#(X-Y)+S_MLE[N1]#Y )    )##3;

L_sss  = 2*(1+2*m)/S_mle[N1]**3 - (2+c_mle[N1])*2*sum_sss[+];


L_gsg=L_ggs; L_sgg=L_ggs;
L_ssg= L_gss ;
**************************************************************************************************;

*** Joint Prior ***;
*** P[1] is the partial derivative of p w.r.t. gamma;
*** P[2] is the partial derivative of p w.r.t. s;

P=J(2,1,0);

P[1]=(a1-1)/gamma_mle[N1]-(a2-1)/(1-gamma_mle[N1]);

p[2]=(mu-1)/S_mle[N1]-lambda; 

******** Fisher Matrix *****;

sigma= J(2,2,0);
Fisher=J(2,2,0);

Sum_I11=S_mle[N1]**2#(X-Y)##2/( 1+gamma_MLE[N1]#S_MLE[N1]#(X-Y)+S_MLE[N1]#Y  )##2;

Fisher[1,1]= -m/(1-gamma_mle[N1])**2 - m/gamma_mle[N1]**2 + (2+C_mle[N1])*Sum_I11[+];

Sum_I12= - S_mle[N1]#(X-Y)#( gamma_mle[N1]#(X-Y)+Y )/ (  1+gamma_MLE[N1]#S_MLE[N1]#(X-Y)+S_MLE[N1]#Y  )##2  
           +   ( X-Y )/ (  1+gamma_MLE[N1]#S_MLE[N1]#(X-Y)+S_MLE[N1]#Y  ); 

Fisher[1,2]= -( 2+c_mle[N1] )* Sum_I12[+];

Fisher[2,1]=Fisher[1,2];

Sum_I22= ( gamma_mle[N1]#(X-Y)+Y )##2/( 1+gamma_MLE[N1]#S_MLE[N1]#(X-Y)+S_MLE[N1]#Y  )##2 ;
Fisher[2,2]= - (1+2*m)/S_MLE[N1]**2 +( 2+c_mle[N1] )* Sum_I22[+];


sigma=inv(fisher); 


*******************************************************************************;
*****************************  Linex Loss Function ****************************;
*******************************************************************************;

U=exp(-z*gamma_mle[N1]); U_g = - z*exp(-z*gamma_mle[N1]);  U_gg = z**2 *exp(-z*gamma_mle[N1]);

Exp_Lin_g = U + 0.5* U_gg* sigma[1,1] -
           U_g *( sigma[1,1]*( p[1] + L_gsg* sigma[1,2] )+ sigma[1,2]*( p[2] + L_gss* sigma[1,2] ) )-
		 U_g/2 *( sigma[1,1]**2 *L_ggg+ sigma[1,1]*( sigma[1,2]*L_ssg+ sigma[2,2]*L_ssg)+ sigma[1,2]*L_sss*sigma[2,2] );                                                                                



gamma_Lin[N1]= - Func1(Exp_Lin_g)/z;

end; * End Of Simulations;



Linex=gamma_Lin[:];




Bias_Lin=abs(gamma_Lin[:]-gamma);

MSE_Lin=(gamma_Lin-gamma_Lin[:])`*(gamma_Lin-gamma_Lin[:])/k;

print  MSE_Lin bias_lin;

  


quit;

 

 

3 REPLIES 3
Rick_SAS
SAS Super FREQ

I'm sorry that I don't have time to carefully analyze your program. However, an initial glance causes me to wonder why Exp_Lin_g is not positive. By its name, I assume you think it is equal to (or an approximation of) EXP(t) for some t. I suggest you review that computation and check that Fisher matrix is computed correctly.  The matrix should be symmetric and positive definite. 

 

Regarding your question, the loss function is scalar, so I assume you are always calling Func1 with a scalar value and returning a scalar value. If so, the function reduces to the SafeLog function, which is Func1(x) = log(x) when x>0 and missing otherwise. At the end of the simulation, you compute the mean of gamma_Lin, so the missing values do not contribute to the mean.  From what I can see, a missing value is the correct return value from Func1.  However, the BEST solution is to track down and understand why Exp_Lin_g is negative.

Salah
Quartz | Level 8

Thank you so much Rick for checking my problem. I believe you are right. Something is wrong with the fisher matrix.

 

 

 

Salah
Quartz | Level 8

 

Hi Rick,

 

I fixed the Fisher matrix, it is positive definite and symmetric. Unfortunately this didn't help with the values of Exp_Lin_g. I still get negative values. Exp_Lin_g must be a number between 0 and 1 as the estimate must be >0, hence  - Log(Exp_Lin_g)>0

Upon checking my code carefully I was surprised to find the following:

 

(1) I get troubles with certain choices of the seed (negative values for Exp_Lin_g) can't tell which seeds as they keep changing!!!!

(2) I couldn't explain or understand how choosing the initials that provide the highest value for the likelihood creates errors while choices such as 1.5 and 3 which do not maximize the likelihhod function won't really work ( i.e. Exp_Lin_g<0,  Exp_Lin_g depends heavily on the MLE).

Proc iml;

seed1=123;seed2=456;seed=0;
m=20; C=10;a1=2; a2=3;
********************** Initial values for alpha1 and alpha2 for the Bayes case *************************;

Prior_a1=J(10000,1,0);	Prior_a2=J(10000,1,0);prior_g=J(10000,1,0);
Do I=1 to 10000;
	 Prior_a1[i]=rangam(seed,a1); Prior_a2[i]=rangam(seed,a2); prior_g[i]=Prior_a1[i]/(Prior_a1[i]+Prior_a2[i]);
end; 			
alpha1=Prior_a1[:]; alpha2=Prior_a2[:];	gamma=prior_g[:];
*********************************************************************;
/*    write the log-likelihood function for bivariate Lomax dist      */
***********************************************************************;

start LogLik(param) global (m,X,Y);
	 f=0; alpha1=param[1]; alpha2=param[2]; c=param[3];
  	 sum=log(1+alpha1*X+alpha2*Y) ;
     f=f+m*log( alpha1*alpha2*c*(1+c) )-(c+2)*sum[+];
     return(f);
     finish;

*****************************************************************************;
** Simulating data from bivariate Lomax with parameters alpha1, alpha2 and C ;
*****************************************************************************;
X=J(m,1,0);Y=J(m,1,0);

U1=J(m,1,0);U2=J(m,1,0);

do i=1 to m;
	U1[i]=Uniform(seed1);
	U2[i]=Uniform(seed2);

	X[i]=( (1-U1[i])**(-1/c) -1 )/alpha1; ** Simulating X from f(x);
	
	Y[i]=(1+alpha1*X[i])/alpha2*( (1-U2[i])**(-1/(1+c)) -1   );  ** Simulating y from f(Y|x);

end;

/* optional: test the module */

params = {	1.5 3 10, 0.9 0.9 10, 0.9 .1 10, 0.1 0.9 10,  0.7 0.7 10,  0.7 1 10,4 6 10,5 4 10,  5.5 4 10,
		   1 0.7 10, 1.5 5 10, 1.5 5.5 10, 1.5 6 10, 5 1.5 10, 5.5 1.5 10, 6 1.5 10,5 5 10,5 5.5 10,
		   2 2 10, 2 5 10, 2 5.5 10, 2 6 10, 5 2 10, 5.5 2 10, 6 2 10, 6 4 10, 5 6 10,
		  3 5 10, 3 5.5 10, 3 6 10,  5 3 10, 5.5 3 10, 6 3 10,4 5 10,4 5.5 10,5.5 5 10,6 5 10};
		  
LogLik = j(nrow(params),1);
do i = 1 to nrow(params);
   p = params[i,];
   LogLik[i] = LogLik(p);
   
end;
results = LogLik || Params;
call sort(results, 1, 1);  /* decreasing by loglik */
print (results[1:30, ])[c={"LogLik" "alpha1" "alpha2" "C"} L="results"]; 
call scatter(1:nrow(results), results[,1]);

quit;



(3) Increasing the stimulation size results on increasing the chances of getting awful values for Exp_Lin_g...I mean getting large negative/positive values such as -2.12 or  3.7!!!!!

 

 

(4) Replacing negative values with missing values is not working. I called it "gamma_lin_Rick and as you see in the pic below it is negative and it supposed to be "."!!!!

Spoiler
Spoiler
Spoiler
Capture11.PNG

I am attaching my code below.  Thank you Rick.

Proc iml;

*seed1=2; *seed2=22; *These choices are working sometimes;

*seed1=123; *seed2=0; seed1=123; seed2=456;

m=10;K=1000;

a1=1.5;a2=2;
a1=1.5; a2=3; /*this choice caused mistakes*/

C=10;z= 1;mu=3;lambda=2 ;  *Initial values for S;

* Initial values for r and S for the Bayes case **;

Prior_a1=J(10000,1,0);	Prior_a2=J(10000,1,0);prior_g=J(10000,1,0);
Do I=1 to 10000;
	 Prior_a1[i]=RAND('GAMMA',a1);
	 Prior_a2[i]=RAND('GAMMA',a2);
	 prior_g[i]= RAND('BETA',a1,a2);
end; 			*DO LOOP OF THE GAMMA;
alpha1=Prior_a1[:]; *true value for alpha1;
alpha2=Prior_a2[:];	*true value for alpha2;

gamma= prior_g[:];

***********************************************************************;
*** 					Log likelihood function
************************************************************************;
start LogLik(param) global (m,X,Y);
	
    f=0;     alpha1=param[1];     alpha2=param[2]; 	c=param[3];
       
    sum=log(1+alpha1*X+alpha2*Y) ;
    f=f+m*log( alpha1*alpha2*c*(1+c) )-(c+2)*sum[+];
    return(f);
    finish;

**************************************************************;
/* Trap bad domain values; return missing values when x outside domain */

start Func1(x);
   f = j(nrow(x), ncol(x), .);    /* initialize return values to missing */
   d1 = x;
   domainIdx = loc( d1>0 );     /* find values inside domain */
   if ncol(domainIdx)=0 then return(f); /* all inputs invalid; return missing */
    t = x[domainIdx];              /* elements of t are valid */
   numer = log(t);
   f[domainIdx] = numer;  /* evaluate f(t) */
   return( f );
finish;


/*  The part below is for simulating data from Bivariate Lomax*/

C_MLE=J(k,1,0); gamma_mle=J(k,1,0);S_mle=J(k,1,0);
gamma_Lin=J(k,1,0);  gamma_Lin_Rick=J(k,1,0);Exp_Lin_g=J(k,1,0);

X=J(m,1,0);Y=J(m,1,0);

Do N1=1 to K;

U1=J(m,1,0);U2=J(m,1,0);

do i=1 to m;

	U1[i]=Uniform(seed1);
	U2[i]=Uniform(seed2);

/* the method below is a better way for simualtion,I wanted to control the seed so I can figure out what went wrong!!!!!
/* But I failed!!!!!! 

	*U1[i]=RAND('UNIFORM');
	*U2[i]=RAND('UNIFORM');
								*/	

	X[i]=( (1-U1[i])**(-1/c) -1 )/alpha1;
	
	Y[i]=(1+alpha1*X[i])/alpha2*( (1-U2[i])**(-1/(1+c)) -1   );

end;

/* End of the simulation */


***************  Optimization Step to find MLEs *********************;

************* Constrain***********************;

    con={1.e-6 1.e-6 1.e-6, . . .};
    opt={1};  
   	x0=alpha1||alpha2||c; *initial guess done by SAS;
	tc={10000 15000};

***************  NLPQN for the Lomax function *********************;

call  NLPNRA(rc, param_ret, "LogLik", x0, opt, con,tc);
alpha1_mle=param_ret[1];
alpha2_mle=param_ret[2];
c_mle[N1]=param_ret[3];
Gamma_mle[N1]=alpha1_mle/(alpha1_mle+alpha2_mle);
S_mle[N1]=(alpha1_mle+alpha2_mle);

************************************************************************************;
*************     Derivations For Lindleys method             **********************;
************************************************************************************;
**L_ggg: derivative w.r.t gamma-gamma-gamma ;
**L_ggs: derivative w.r.t. gamma-gamma-S;

sum_ggg=(   S_mle[N1]#(X-Y)/( 1+gamma_MLE[N1]#S_MLE[N1]#(X-Y)+S_MLE[N1]#Y )    )##3;

L_ggg=-2*m/(1-gamma_mle[N1])**3 +  2*m/gamma_mle[N1]**3 -2*(2+c_mle[N1])* sum_ggg[+];

*************************************************************************************; 
 
sum_ggs1=( 2# S_mle[N1]**2#(X-Y)##2#(gamma_mle[N1]#(X-Y)+Y ))/( 1+gamma_MLE[N1]#S_MLE[N1]#(X-Y)+S_MLE[N1]#Y ) ##3 ;
sum_ggs2=( 2# S_mle[N1]#(X-Y)##2/( 1+gamma_MLE[N1]#S_MLE[N1]#(X-Y)+S_MLE[N1]#Y )    )##2;

L_ggs= -(2+c_mle[N1]) *(sum_ggs1[+]-sum_ggs2[+])   ;
**************************************************************************;
sum_gss1= 2# S_mle[N1]#(X-Y)#( gamma_mle[N1]#(X-Y)+Y )##2 /( 1+gamma_MLE[N1]#S_MLE[N1]#(X-Y)+S_MLE[N1]#Y ) ##3 ;
sum_gss2=2# (X-Y) #( gamma_MLE[N1]#(X-Y)+Y )/( 1+ gamma_MLE[N1]#S_MLE[N1]#(X-Y)+S_MLE[N1]#Y     )##2;

L_gss= -(2+c)*( sum_gss1[+] - sum_gss2[+]  );
 
*********************************************************************;
********************************************************************;
sum_sss=( (gamma_mle[N1]#(X-Y)+Y )/( 1+gamma_MLE[N1]#S_MLE[N1]#(X-Y)+S_MLE[N1]#Y )    )##3;

L_sss  = 2*(1+2*m)/S_mle[N1]**3 - (2+c_mle[N1])*2*sum_sss[+];

L_gsg=L_ggs; L_sgg=L_ggs;
L_ssg= L_gss ;
***********************************************************************************;

*** Joint Prior ***;

P=J(2,1,0);

P[1]=(a1-1)/gamma_mle[N1]-(a2-1)/(1-gamma_mle[N1]);
p[2]=(mu-1)/S_mle[N1]-lambda; 

******** Fisher Matrix *****;
sigma= J(2,2,0);
Fisher=J(2,2,0);

Sum_I11=S_mle[N1]**2#(X-Y)##2/( 1+gamma_MLE[N1]#S_MLE[N1]#(X-Y)+S_MLE[N1]#Y  )##2;

Fisher[1,1]= -(-m/(1-gamma_mle[N1])**2 - m/gamma_mle[N1]**2 + (2+C_mle[N1])*Sum_I11[+]);

Sum_I12= - S_mle[N1]#(X-Y)#( gamma_mle[N1]#(X-Y)+Y )/ (  1+gamma_MLE[N1]#S_MLE[N1]#(X-Y)+S_MLE[N1]#Y  )##2  
           +   ( X-Y )/ (  1+gamma_MLE[N1]#S_MLE[N1]#(X-Y)+S_MLE[N1]#Y  ); 

Fisher[1,2]= ( 2+c_mle[N1] )* Sum_I12[+];

Fisher[2,1]=Fisher[1,2];

Sum_I22= ( gamma_mle[N1]#(X-Y)+Y )##2/( 1+gamma_MLE[N1]#S_MLE[N1]#(X-Y)+S_MLE[N1]#Y  )##2 ;
Fisher[2,2]= (2*m)/S_MLE[N1]**2 -( 2+c_mle[N1] )* Sum_I22[+];

sigma=inv(fisher); 

 *print (eigval(sigma)); /*this is to check is sigma is positive definite*/
*******************************************************************************;
*****************************  Linex Loss Function ****************************;
*******************************************************************************;

U=exp(-z*gamma_mle[N1]); U_g = - z*exp(-z*gamma_mle[N1]);  U_gg = z**2 *exp(-z*gamma_mle[N1]);

x1=0.5* U_gg* sigma[1,1];
x2=sigma[1,1]*( p[1] + L_gsg* sigma[1,2] );
x3=sigma[1,2]*( p[2] + L_gss* sigma[1,2] );
x4=sigma[1,1]**2 *L_ggg;
x5=sigma[1,1]*( sigma[1,2]*L_ggs+ sigma[2,2]*L_ssg);
x6=sigma[1,2]*L_sss*sigma[2,2];

Exp_Lin_g[N1] = U + x1 + U_g *( x2 + x3 )+ 0.5 *U_g *( x4+ x5+ x6 );                                                                                

gamma_Lin_Rick[N1]= -Func1(Exp_Lin_g[N1])/z;

gamma_Lin[N1]= -Log(Exp_Lin_g[N1])/z;

end; * End Of Simulations;

Estimate_Linex=gamma_Lin[:];

MSE=(gamma_Lin-gamma_Lin[:])`*(gamma_Lin-gamma_Lin[:])/k;

print Estimate_Linex " " MSE;

print gamma_Lin gamma_Lin_Rick ;

quit;

 

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