Hi,
Is there a way to operate with symbols (variables x, y, etc) on SAS? Like 2x+3x=5x or exp(2*3+1-x/2)=exp(7-0.5*x) ?
I searched for it online and couldnt find anything. And I think it's kind of a long shot, because SAS is more for data analysis, but since some mathematical softwares do it, I thought I'd ask.
Sure, I mean, symbols are implemented as variables in SAS, and the formulas you provide can be coded in the data step, SQL to name a few places.
Can you give a bit more context how you wish to use this?
I constructed a model (logistic regression) with 12 explanatory variables, so I have the model function y = f(x_1, x_2, ..., x_12). Besides, I have another function that depends on one of this variables, say z=g(x_1). Now, I need tho solve the equation for x_1:
f(x_1,...,x_12)*g(x_1)=Lambda,
where Lambda is some constant.
As I was writing this reply, I realized it is more than I asked in the original question, but the operating with symbols seemed a good place to start and I didn't find anything online.
Isn't this for modelling with nonlinear types of equation? I read some of the documentation and didn't find it related... I wanted the "pure" mathematical expression thats solves the equation.
You may need to clarify what you mean by your question.
Do you mean if a SAS data set variable contains such calculations can it be used to perform the calculations?
Or do you mean to manipulate the text of a value to a different equivalent form?
Where are these operations stored?
In general, it is impossible to solve the equation f(x_1,...,x_12)*g(x_1)=Lambda for x_1. Symbolic math software (such as Mathematica or the free version at WolframAlpha.com) can invert simple equations such as low-order polynomials, and I think that is what you are asking about. No, SAS does not contain a symbolic algebra system.
However, for any specified value of Lambda, you can NUMERICALLY solve for the value of x_1 that satisfies the equation by finding the root (zero) of the equation f(x_1,...,x_12)*g(x_1) - Lambda = 0. This is a one-dimensional root-finding problem, so can be solved in many ways. See
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