BookmarkSubscribeRSS Feed

Finde out who belong to the same household

Started ‎04-23-2014 by
Modified ‎10-05-2015 by
Views 6,430

Details see the following URL.

 

And here is the code I offered, Hope can help other people.

 

 

data have;
infile cards delimiter='|';
/*from is parent, to is child*/
input from $  to $ ;
cards;
        2    |    4  
        2    |    5  
        2    |    6  
        2    |    8
        4    |    7  
        4    |    11  
        6    |    9  
        6    |    10
        6    |    12
        10  |    15  
        10  |    16  
        13  |    14  
        16  |    17
          99|2
          7|4
          100|20
;
run;
data full;
  set have end=last;
  if _n_ eq 1 then do;
   declare hash h();
    h.definekey('node');
     h.definedata('node');
     h.definedone();
  end;
  output;
  node=from; h.replace();
  from=to; to=node; output;
  node=from; h.replace();
  if last then h.output(dataset:'node');
  drop node;
run;


data want(keep=node household);
declare hash ha(ordered:'a');
declare hiter hi('ha');
ha.definekey('count');
ha.definedata('last');
ha.definedone();
declare hash _ha(hashexp: 16);
_ha.definekey('key');
_ha.definedone();

if 0 then set full;
declare hash from_to(dataset:'full',hashexp:20,multidata:'y');
 from_to.definekey('from');
 from_to.definedata('to');
 from_to.definedone();

if 0 then set node;
declare hash no(dataset:'node');
declare hiter hi_no('no');
 no.definekey('node');
 no.definedata('node');
 no.definedone();
 

do while(hi_no.next()=0);
 household+1; output;
 count=1;
 key=node;_ha.add();
 last=node;ha.add();
 rc=hi.first();
 do while(rc=0);
   from=last;rx=from_to.find();
   do while(rx=0);
     key=to;ry=_ha.check();
      if ry ne 0 then do;
       node=to;output;rr=no.remove(key:node);
       key=to;_ha.add();
       count+1;
       last=to;ha.add();
      end;
      rx=from_to.find_next();
   end;
   rc=hi.next();
end;
ha.clear();_ha.clear();
end;
stop;
run;

    
 
 


 

 

Xia Keshan

Comments

Hi, I tried executing  this logic. But  its showing error of duplicate key and also, it gives output of same node against multiple households.

The problem is here :

declare hash from_to(dataset:'full',hashexp:20,multidata:'y');

Should be 

declare hash from_to(dataset:'full',hashexp:20,multidata:'y');

 

Version history
Last update:
‎10-05-2015 03:50 PM
Updated by:

hackathon24-white-horiz.png

The 2025 SAS Hackathon Kicks Off on June 11!

Watch the live Hackathon Kickoff to get all the essential information about the SAS Hackathon—including how to join, how to participate, and expert tips for success.

YouTube LinkedIn

SAS AI and Machine Learning Courses

The rapid growth of AI technologies is driving an AI skills gap and demand for AI talent. Ready to grow your AI literacy? SAS offers free ways to get started for beginners, business leaders, and analytics professionals of all skill levels. Your future self will thank you.

Get started

Article Labels
Article Tags