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d6k5d3
Pyrite | Level 9

For a dataset like the following one:

data example;
input interval zzz;
cards;
99 .345
100 -.398
101 .546
102 .968
103 -.012
104 .489
105 .005;
run;

how can I create 1 lead in variable zzz? I have found people recommending about PROC EXPAND, but I could not work that out. Would you please help?

 

Thank you.

 

Regards.

1 ACCEPTED SOLUTION

Accepted Solutions
PGStats
Opal | Level 21

People recommending proc expand were right, as long as you have SAS/ETS licenced

 

proc expand data=example out=want;
id interval;
convert zzz=zzz_lead / transformout=(lead 1);
run;
PG

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4 REPLIES 4
Astounding
PROC Star

So what should the results look like?  Does the final observation get deleted?

Tom
Super User Tom
Super User

Not sure if there is a BEST way. Here is an easy way.  I assume you meant to include that last line of data in your example?

data example;
input interval zzz;
cards;
99 .345
100 -.398
101 .546
102 .968
103 -.012
104 .489
105 .005
;

data want ;
  set example;
  set example(firstobs=2 keep=zzz rename=(zzz=zzz_lead1)) example(obs=1 drop=_all_);
run;
                              zzz_
Obs    interval      zzz      lead1

 1         99       0.345    -0.398
 2        100      -0.398     0.546
 3        101       0.546     0.968
 4        102       0.968    -0.012
 5        103      -0.012     0.489
 6        104       0.489     0.005
 7        105       0.005      .
PGStats
Opal | Level 21

People recommending proc expand were right, as long as you have SAS/ETS licenced

 

proc expand data=example out=want;
id interval;
convert zzz=zzz_lead / transformout=(lead 1);
run;
PG
d6k5d3
Pyrite | Level 9
Awesome! Worked fine!

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