Hey all,
I can't seem to find a quick way of doing this. I have a string variable, and if the 3rd character is a number, it is indicative of a business, if it is a letter it is an individual. What is the easiest way to determine this?
I have tried marker = (substr(var,3,1) IN(0:9)); but then when it's text, it gives errors.
Thanks!
Try this:
data have;
input string$ @@;
cards;
adsflk ad2eif ad0euh
;
data want;
set have;
Digiornot=anydigit(substr(string,3,1));
put '1-Digit 0-None Digit' digiornot=;
run;
Haikuo
Try this:
data have;
input string$ @@;
cards;
adsflk ad2eif ad0euh
;
data want;
set have;
Digiornot=anydigit(substr(string,3,1));
put '1-Digit 0-None Digit' digiornot=;
run;
Haikuo
Thanks!
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