Rick -
so there will always only be 2 first columns corresponding to the covariance matrix parameter indices. so imagine a 4x4 covariance matrix (which is symmetric) with the indices (1,1) (1,2) (1,3) (1,4) (2,2) (2,3) , ect. the fact that it is symmetric allows us not to worry about (2,1) (3,1) (3,2) and so on. now that i think about it ordered permuations was not the correct way to describe that.
once we have the indices then we add 4 more columns (or in general if the covariance matrix is nxn then we add n more columns) corresponding to ones starting at the first number of the index.
so the row starting with (2,3) will be 2 3 0 1 1 1
thus we will have zeros up the first index-1 (in this example 2-1=1 and then starting at 2 we have all ones
Message was edited by: trekvana
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