If condition with macro variables

[CurtisMackWSIPP]

The value is always false because you are always comparing "X" to "2" from dataset X.  You aren't accessing anything from dataset Y.

[CurtisMackWSIPP]

I suspect you could solve this with a custom made format.

[Aman4SAS]

Same is working , diff is not proc sql to create macro varible;
Code:
%GLOBAL FLAG;
%MACRO TEST();
%LET VAR=NAME;
%LET SEX=M;
%LET COND= =;
%IF &VAR &COND %BQUOTE('&SEX') %THEN %LET FLAG=Y;
%ELSE %LET FLAG=N;
%MEND;
DATA NEW;
SET SASHELP.CLASS;
CALL EXECUTE('TEST();');
FLAG=CALL SYMGET('FLAG');
RUN;

Its working fine.

Plz help

[PaigeMiller]

You can't refer to DATA set variables like NAME using a macro variable &VAR inside a macro. When you use &VAR to refer to a data set variable, you must use it inside a SAS data step. If you want to compare a data set variable to some other value, it must be done in a DATA step, using a data step IF statement and not a macro %IF statement, which only compares macro variables to a value.

So nothing you are trying to do with this macro will work.

You could, however, create code like this, that works inside a DATA step

%LET VAR=NAME;
%LET SEX=M;
%LET COND= =;

data want;
    set sashelp.class;
    if &var &cond "&sex" then flag='Y';
run;

Of course, your logic still fails, but the code produces no errors. Why does the code work now? Because &VAR is replaced with NAME and &COND is replaced by = and &SEX is replaced by M, yielding the line of code if name="M" then flag='Y'; inside a DATA step, which is indeed valid SAS code.

The logic fails because there are no observations in SASHELP.CLASS for which the variable NAME is equal to the value of "M". But I leave that up to you to fix.

[PaigeMiller]

Adding to my reply above

Here's a macro that does what you want

%macro subset(dsn=,var=,cond=,value=);
data want;
    set &dsn;
    if &var &cond "&value" then flag='Y';
run;
%mend;

/* Example: */
%subset(dsn=sashelp.class,var=name,cond=%str(=),value=Jane)

/* Example 2: */
%subset(dsn=sashelp.class,var=name,cond=%str(=:),value=J)

Works when &var references a data set character variable. Note that the comparison of the data step variable is done in a data step IF statement and not in a macro %IF statement, which cannot compare data step variables to a value.