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Reeza
Super User

I typically do something like the following. But as BallardW has indicated, your results don't match your question.

data have;

input Slno Q1_1 Q1_2 Q1_3;

cards;

1    1    0    1

2    0    .    0

3    1    1    0

4    1    .    0

5    1    1    1

6    0    .    1

7    0    1    1

8    1    0    1

9    1    .    1

10    1    0    0

;

run;

data step1;

    set have;

    array ques(3) q1_1 q1_2 q1_3;

    do i=1 to dim(ques);

        response=ques(i);

        question=vname(ques(i));

        output;

    end;

run;

proc means data=step1 n sum mean;

class question;

var response;

run;

proc freq data=step1;

table question*response/list missing;

run;

2 REPLIES 2
tadiboinak
Calcite | Level 5

hi Reeza,

The solution array given by you worked perfectly but unfortunately is not the solution as the observations are increasing as a result of the array,

For example i have 30 respondents. when i am using an array it increases to 90 respondents.

I am attaching a sample files for your perusal. Request you to kindly go through the file and suggest a soultion.

Thanks,

Saikiran

Reeza
Super User

It will increase to 90 observations, # of respondents *# of questions - in this case, 30 * 3= 90.

You basically have Person*Question level data instead of person level data now.

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