I typically do something like the following. But as BallardW has indicated, your results don't match your question.
data have;
input Slno Q1_1 Q1_2 Q1_3;
cards;
1 1 0 1
2 0 . 0
3 1 1 0
4 1 . 0
5 1 1 1
6 0 . 1
7 0 1 1
8 1 0 1
9 1 . 1
10 1 0 0
;
run;
data step1;
set have;
array ques(3) q1_1 q1_2 q1_3;
do i=1 to dim(ques);
response=ques(i);
question=vname(ques(i));
output;
end;
run;
proc means data=step1 n sum mean;
class question;
var response;
run;
proc freq data=step1;
table question*response/list missing;
run;
hi Reeza,
The solution array given by you worked perfectly but unfortunately is not the solution as the observations are increasing as a result of the array,
For example i have 30 respondents. when i am using an array it increases to 90 respondents.
I am attaching a sample files for your perusal. Request you to kindly go through the file and suggest a soultion.
Thanks,
Saikiran
It will increase to 90 observations, # of respondents *# of questions - in this case, 30 * 3= 90.
You basically have Person*Question level data instead of person level data now.
Available on demand!
Missed SAS Innovate Las Vegas? Watch all the action for free! View the keynotes, general sessions and 22 breakouts on demand.
Learn how use the CAT functions in SAS to join values from multiple variables into a single value.
Find more tutorials on the SAS Users YouTube channel.