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sasuser1
Calcite | Level 5

Data abc;

input start_date $10.;

cards;

2008-06-31

;

run;

I am trying to convert the about date into the date format 31/06/2008.

Could you please any one help in getting this resolved?

3 REPLIES 3
DBailey
Lapis Lazuli | Level 10

I don't think that's a valid date?  If it was, it should be a simple matter to read it in as a date and apply the ddmmyy10. format.

Linlin
Lapis Lazuli | Level 10

Hi,

there were only 30 days in June.

Data abc;

input start_date $10.;

cards;

2008-06-30

;

data want;

  set abc;

   new_date=input(start_date,yymmdd10.);

  format new_date ddmmyy10.;

  proc print;run;

Reeza
Super User

Or directly in the input step is possible.

Data abc;

informat start_date yymmdd10.;

format start_date date9.;

input start_date;

cards;

2008-06-30

2008-06-31

2008-07-01

;

run;

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