May I ask you if my interpretation of SAS results are correct. thanks !!!
my data has a class variable u_rank, it takes on two values 1, and 4,
my test variable is disclose (a continuous variable).
I use proc npar1way to test difference in median of disclose between u_rank=1 and u_rank=4.
see below for code (attached)
my interpretation is :
median is zero for both u_rank=1 or 4
I am not certain:
The NPAR1WAY shows z value to be significant.
could I conclude : even though median value of disclose is 0 for both u_rank=1 and u_rank=4 , but median test still shows significant difference between the class variable u_rank?
thanks !!!
Lan
Yes you could. Your data likely has a fair proportion of disclose=0 observations in both u_rank groups. Run the following simulation:
data test;
call streaminit(987676);
do u_rank = 1, 4;
do i = 1 to 2520;
if mod(i, 2) then disclose = 0;
else disclose = rand("NORMAL", u_rank*0.05);
output;
end;
end;
drop i;
run;
proc univariate data=test;
class u_rank;
var disclose;
histogram;
run;
proc npar1way data=test median wilcoxon;
class u_rank;
var disclose;
run;
PG
Yes you could. Your data likely has a fair proportion of disclose=0 observations in both u_rank groups. Run the following simulation:
data test;
call streaminit(987676);
do u_rank = 1, 4;
do i = 1 to 2520;
if mod(i, 2) then disclose = 0;
else disclose = rand("NORMAL", u_rank*0.05);
output;
end;
end;
drop i;
run;
proc univariate data=test;
class u_rank;
var disclose;
histogram;
run;
proc npar1way data=test median wilcoxon;
class u_rank;
var disclose;
run;
PG
Thanks so much, PG .
Available on demand!
Missed SAS Innovate Las Vegas? Watch all the action for free! View the keynotes, general sessions and 22 breakouts on demand.
Learn how use the CAT functions in SAS to join values from multiple variables into a single value.
Find more tutorials on the SAS Users YouTube channel.