Hello,
I have the following problem. I want to keep each line in a month where b is a maximum. For example, this is what I will keep :
Thank you for your help
/* UNTESTED CODE */
proc sql; create table want as select * from have group by mdy(month(f1),1,year(f1)) having b=max(b); quit;
/* UNTESTED CODE */
proc sql; create table want as select * from have group by mdy(month(f1),1,year(f1)) having b=max(b); quit;
Something like:
data inter; set have; mnth=month(f1); run; proc sort data=inter out=want; by mnth descending b; run; data want; set want; by mnth; if first.mnth; run;
Or you could do it in SQL by
proc sql; create table WANT as select * from have group by month(f1) having b=max(b); quit;
Or proc summary, or means.
@RW9 This works if all the dates are in the same year, doesn't work if the dates span multiple years.
He never mentioned that, if so just change the month() function for a put():
proc sql; create table WANT as select * from have group by put(f1,mmyy6.) having b=max(b); quit;
Obviously not tested as don't have time to type his test data in.
Available on demand!
Missed SAS Innovate Las Vegas? Watch all the action for free! View the keynotes, general sessions and 22 breakouts on demand.
Learn how use the CAT functions in SAS to join values from multiple variables into a single value.
Find more tutorials on the SAS Users YouTube channel.