I have this data:
ID Start_DT End_DT
a 01/01/2016 01/02/2016
a 01/02/2016 01/04/2016
b 02/03/2016 02/04/2016
b 02/05/2016 02/07/2016
c 04/05/2016 04/07/2016
I want to create a Admit_ID like this:
ID Start_DT End_DT Admit_ID
a 01/01/2016 01/02/2016 1
a 01/02/2016 01/04/2016 1
b 02/03/2016 02/04/2016 2
b 02/05/2016 02/07/2016 2
c 04/05/2016 04/07/2016 3
if row one and row 2 are same and the End_DT in row one is the same as the Start_DT at row two, they get same Admit_ID or The End_DT of the row is one day apart from the start_DT of the next row like row 3 and row 4, the two rows still get same Admit_ID; otherwise they get different Admit_ID like row 5.
Indeed!
there are 2 errors that correct each other! This is better:
data HAVE;
input ID $1. START_DT : mmddyy10. END_DT : mmddyy10.;
format START_DT END_DT date9.;
cards;
a 01/01/2016 01/02/2016
a 01/02/2016 01/04/2016
b 02/03/2016 02/04/2016
b 02/05/2016 02/07/2016
c 04/05/2016 04/07/2016
run;
data WANT;
set HAVE;
PREV_ID =lag(ID);
PREV_END_DT =lag(END_DT);
if ID ne PREV_ID | START_DT-PREV_END_DT ^in (0,1) then ADMIT_ID+1;
drop PREV:;
run;
proc print noobs; run;
Like this?
data HAVE;
input ID $1. START_DT : mmddyy10. END_DT : mmddyy10.;
format START_DT END_DT date9.;
cards;
a 01/01/2016 01/02/2016
a 01/02/2016 01/04/2016
b 02/03/2016 02/04/2016
b 02/05/2016 02/07/2016
c 04/05/2016 04/07/2016
run;
data WANT;
set HAVE;
LAG_ID =lag(ID);
LAG_START_DT=lag(START_DT);
if ID ne LAG_ID | END_DT-LAG_START_DT in (0,1) then ADMIT_ID+1;
drop LAG:;
run;
proc print noobs; run;
ID | START_DT | END_DT | ADMIT_ID |
---|---|---|---|
a | 01JAN2016 | 02JAN2016 | 1 |
a | 02JAN2016 | 04JAN2016 | 1 |
b | 03FEB2016 | 04FEB2016 | 2 |
b | 05FEB2016 | 07FEB2016 | 2 |
c | 05APR2016 | 07APR2016 | 3 |
Chris, I think you have the right idea. But I'm not sure about one piece. Shouldn't the subtraction look at:
START_DT - LAG_END_DT
Indeed!
there are 2 errors that correct each other! This is better:
data HAVE;
input ID $1. START_DT : mmddyy10. END_DT : mmddyy10.;
format START_DT END_DT date9.;
cards;
a 01/01/2016 01/02/2016
a 01/02/2016 01/04/2016
b 02/03/2016 02/04/2016
b 02/05/2016 02/07/2016
c 04/05/2016 04/07/2016
run;
data WANT;
set HAVE;
PREV_ID =lag(ID);
PREV_END_DT =lag(END_DT);
if ID ne PREV_ID | START_DT-PREV_END_DT ^in (0,1) then ADMIT_ID+1;
drop PREV:;
run;
proc print noobs; run;
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