I have a put c $ in a program and the output looks like this all on one line as output A $PROBLEM TWO PEAK SEQUENTIAL ZERO AND FIRST ORDER$DATA ..\TFIT1.CSV IGNORE=W    However I would like the output to look like this as two seperate lines as output B $PROBLEM TWO PEAK SEQUENTIAL ZERO AND FIRST ORDER $DATA ..\TFIT1.CSV IGNORE=W   My question is how can I format the put c $ statement to get the output to look like output B and not output A?    ... View more

I have the following program which works on the file ref  below but does not seem to work on nref  attached which is not output as a continuous file but seems to be wrapping around.  Can anyone tell me why and how to correct the problem? data _null_ ; infile '/folders/myfolders/bootnew/nREF.CTL' truncover; /* INPUT CHARACTER FILE*/ input c $1000.; do i=1 to 2; myfile='/folders/myfolders/bootnew/nREF' || trim(left(put(i,8.))) || '.ctl'; file dummy filevar=myfile MOD ; if _n_=2 then do; if i=1 then do; amp_loc=index(c,'&'); first_half=substr(c,1,amp_loc-1); last_half=substr(c,amp_loc+2); end; c= trim(first_half) || trim(left(put(i,8.))) || last_half; end; put c $; end; run;   FILE REF: $PROBLEM TWO PEAK SEQUENTIAL ZERO AND FIRST ORDER $DATA ..\TFIT&i.CSV IGNORE=W $INPUT ID TIME DV DOSE CMT AMT EVID MDV $SUB ADVAN5 TRANS1 $MODEL COMP=(1);DOSE1 COMP=(2);DOSE2 COMP=(CENTRAL,DEFOBS);CENTRAL,DEFDOSE) $PK KAS= THETA(1) KAF= THETA(2) CL = THETA(3) V3 = THETA(4) TLAG2= THETA(5) LOGITT = THETA(6) TVF1 = 1/(1+EXP(-LOGITT)) F1 = TVF1 S3= V3/1000 F2=1-F1 K23=KAF ;FIRST ORDER MR TO CENTRAL K13=KAS ;FLOW FROM MR TO CENTRAL K30=CL/V3 ;ELIMINATION FROM CENTRAL $ERROR CP=A(3)/S3 Y=CP +CP*ERR(1) + ERR(2) $THETA (0.05,0.5) ;1)K0 $THETA (0.05,0.8) ;2)KAS $THETA (60, 200) ;3)CL L/HR $THETA (30,100) ;4)V3 L $THETA (0.1,2) ;5)LAG2 HR $THETA (-10.0 -0.04 1 ) ;6)LOGIT F1 $OMEGA 0.01 0.1 $EST METH=0 MAXEVAL=9999 PRINT=5 ;$COVARIANCE ;$SIM (123456) ONLYSIM SUBPROBLEMS=1 $TABLE ID AMT TIME DV CMT Y DOSE KAF KAS CL V3 TLAG2 LOGITT ONEHEADER NOPRINT FILE=MOD.FIT ... View more

ods trace on /listing; ods output estimates=stat1; ods output FITSTATISTICS=stat2; ods output LSMEANCL=stat3; ods output OverallANOVA=stat4; ods output LsmeandiffCL=stat5; ods output LsmeanCL=stat6; proc glm data=new1; class trt; model clnr=trt/ss1 ss2 ss3 ss4; lsmeans trt/pdiff cl alpha=0.10; estimate 'A vs B' trt 1 -1; quit; run; ods trace on /listing ods output estimates=stat7; ods output FITSTATISTICS=stat8; ods output LSMEANCL=stat9; ods output OverallANOVA=stat10; ods output LsmeandiffCL=stat11; ods output LsmeanCL=stat12; proc glm data=newL1; class trt; model Lclnr=trt/ss1 ss2 ss3 ss4; lsmeans trt/pdiff cl alpha=0.10; estimate 'A vs B' trt 1 -1; quit; The code was used to analyze the attached data set  CLnr1.  The outputs from stat6 and stat12 were compared which are the Lsmean CI. Stat6 Obs Effect Dependent TRT LowerCL LSMean UpperCL 1 2 TRT CLnr A 102.984141 114.620000 126.255859 TRT CLnr B 38.763546 47.962500 57.161454   Stat12 Obs Effect Dependent TRT LowerCL LSMean UpperCL 1 2 TRT LCLnr A 4.554136 4.732812 4.911488 TRT LCLnr B 3.699795 3.841051 3.982307 The values of exp(lower CL) and exp(upper CL) give values for A (94-134) and B(40-53) which are close to the values for the normal scale.  However for stat5 for the difference on the normal scale I get: bs Effect Dependent i j LowerCL Difference UpperCL TRT _TRT 1 TRT CLnr 1 2 51.824632 66.657500 81.490368 A B Whereas for stat 11 for the LClnr I get s Effect Dependent i j LowerCL Difference UpperCL TRT _TRT 1 TRT LCLnr 1 2 0.663993 0.891761 1.119529 A B If I do the exp(lowerCL) and exp(UpperCL) I get (1.93-3.03) which is not in agreement with the normal scale.   Can someone explain to me why the normal scale and log scale agree for the CL for A and B but not for the difference between A and B for the normal and log scale? ... View more