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Output Parts of a String

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Accepted Solution

Output Parts of a String

In SAS 9.2

Is there a simple way to split a string?

  1. E.g.

%Let baseString = D1 D2 D3;

For I = 0 to end;

Output D1 the first time;

Output D2 the second time;

Output D3 the third time;

End loop;

I do not want to do this in a data step.


Accepted Solutions
Solution
‎05-20-2015 05:07 PM
Super User
Super User
Posts: 7,039

Re: Output Parts of a String

Posted in reply to DavidPhillips2

SCAN() or %SCAN()

data _null_;

   basestring='D1 D2 D3';

   do i=1 to countw(basestring);

      word = scan(basestring,i);

      put i= word=;

  end;

run;

or

%do i=1 %to %sysfunc(countw(&basestring));

   %let word = %scan(&basestring,&i);

   %put i=&i word=&word;

%end;

View solution in original post


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Contributor
Posts: 50

Re: Output Parts of a String

Posted in reply to DavidPhillips2

Hello,

How about using macro?

Best regards

Solution
‎05-20-2015 05:07 PM
Super User
Super User
Posts: 7,039

Re: Output Parts of a String

Posted in reply to DavidPhillips2

SCAN() or %SCAN()

data _null_;

   basestring='D1 D2 D3';

   do i=1 to countw(basestring);

      word = scan(basestring,i);

      put i= word=;

  end;

run;

or

%do i=1 %to %sysfunc(countw(&basestring));

   %let word = %scan(&basestring,&i);

   %put i=&i word=&word;

%end;

Occasional Contributor
Posts: 7

Re: Output Parts of a String

Posted in reply to DavidPhillips2

Here is a macro that I use that also puts everything you might need into macro variables. (I have just improved it a bit by stealing Tom's idea of using countw).

%MACRO makelist(base,list);

* create a set of macro variables named base1, base2 ... with values from list + list returned as <base>list;

%PUT &base &list;

%GLOBAL n&base &base.list;

%LET &base.list =&list;

%LET n&base=%sysfunc(countw(&list));

%DO i=1 %TO &&n&base;

%GLOBAL &&base&&n&base;

%LET &&base&&n&base=%SCAN(&list,&&n&base);

%END ; ;

%PUT n&base = &&n&base;

%DO i=1 %TO &&n&base;  %PUT &base&i &&&base&i; %END;

%MEND;

%makelist(test,D1 D2 D3);

Then you can reference them with a loop in a macro eg. ...

PROC MEANS;

VAR &testlist; * D1 D2 D3;

OUTPUT OUT=testmeans MEAN=%DO I=1 %TO &ntest; &&test&i..m %END; ;

The output dataset contains means in the variables D1m D2m and D3m.


Super User
Posts: 5,497

Re: Output Parts of a String

Posted in reply to DavidPhillips2
Super Contributor
Posts: 497

Re: Output Parts of a String

Posted in reply to Astounding

data _null_;

degStudLevComma = "aa,b,a";

total = countc(&degStudLevComma, ',');

put "&total";

run;

In order to know when to end going through my string I need to use countc.  My string is delimited by commas.  When I do this I receive an error that I have too many arguments.  I’m guessing this is because my variable has commas in it that are acting like variable separators.

Super User
Super User
Posts: 7,039

Re: Output Parts of a String

Posted in reply to DavidPhillips2

You want the countW() function to see how many items are in your list.  You can included commas if they are properly quoted.

Super Contributor
Posts: 497

Re: Output Parts of a String

This worked.

data _null_;

degStudLevComma = "D1,D2";

total = countw(degStudLevComma, ',');

put total;

run;

or

%macro testMacro();

  %let degStudLevComma = "D1,D2";

  %let total = %sysfunc(countw(&degStudLevComma, ','));

  %put total &total;

%mend;

%testMacro();

Super User
Super User
Posts: 7,039

Re: Output Parts of a String

Posted in reply to DavidPhillips2

Example with embedded commas.

%let x=This,list,has,"5, not 6 or 7,",words;

%let n=%sysfunc(countw(%superq(x),%str(,),qm));

%put &=n;

N=5

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