a cluster analysis (method: Ward) is leading to a meaningful solution if I first run proc Aceclus (p=.04).
But the input data are 2 factors which resulted from a factor analysis. My question is now, if it is admissible to use Aceclus by variables which have the same SD. Or rather, how is the difference to the solution without Aceclus to interpret.
ANOVA, or Analysis Of Variance, is used to compare the averages or means of two or more populations to better understand how they differ. Watch this tutorial for more.