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gencharitaci
Calcite | Level 5

Hi everyone.

I have a data set and I attached it to my message.  You can see it below.

I want to calculate bolt_volume. It looks simple but I couldn't get correct results. The formula has already written in excel sheet.

bolt_volume[row2] = ( bolt_area[row1] + bolt_area[row2] ) / 2 * bolt_len[row2]

bolt_volume[row3] = ( bolt_area[row2] + bolt_area[row3] ) / 2 * bolt_len[row3]

...........

tree_nobolt_nobolt_lenbolt_areabolt_volume
11.235344635
1120.893583362.128927995
1220.8217848591.715368219
20.346877809
2120.2768757190.623753528
2220.2269000350.503775754
30.294638715
3120.1930852350.48772395
3220.1850576290.378142864

Thank you for your help.

1 ACCEPTED SOLUTION

Accepted Solutions
art297
Opal | Level 21

Here is one way:

data want;

  set have;

  by tree_no;

  bolt_volume=ifn(first.tree_no,.,lag(bolt_area)+bolt_area) / 2 * bolt_len;

run;

View solution in original post

9 REPLIES 9
stat_sas
Ammonite | Level 13

Hi,

This should work for the desired output.

Thanks,

Naeem

data want;

set have;

bolt_volume=(bolt_area+lag(bolt_area))/2*bolt_len;

run;

art297
Opal | Level 21

Here is one way:

data want;

  set have;

  by tree_no;

  bolt_volume=ifn(first.tree_no,.,lag(bolt_area)+bolt_area) / 2 * bolt_len;

run;

gencharitaci
Calcite | Level 5

Thanks

art297
Opal | Level 21

Just be careful with Naeem's code as it will give you non-missing, and wrong values, for the 1st record of the 2nd thru Nth by groups.

gencharitaci
Calcite | Level 5

@,

My original data set has more than 2000 observations. After I saw your message, I checked your codes and Nadeem's codes for my data set. But I couldn't see wrong values 1st record of the 2nd through Nth by groups.

art297
Opal | Level 21

I stand corrected!  I hadn't noticed that bolt_len was always missing for your first record within an id.  If that is the case in all situations, then Naeem's code will provide the correct result.

stat_sas
Ammonite | Level 13

Thanks Arthur - Yes, if first id is not missing then your suggested solution is a definite choice.

Regards,

Naeem

gencharitaci
Calcite | Level 5

Ok. I see now. That's tender spot.

Thanks Arthur.

Justin_Allison
Calcite | Level 5

An operator in SAS is a symbol which is used in a mathematical, logical or comparison expression.

 

Example Arithmetic Operators.

 

DATA MYDATA1;
input @1 COL1 4.2 @7 COL2 3.1;
Add_result = COL1+COL2;
Sub_result = COL1-COL2;
Mult_result = COL1*COL2;
Div_result = COL1/COL2;
Expo_result = COL1**COL2;
datalines;
11.21 5.3
3.11 11
;
PROC PRINT DATA=MYDATA1;
RUN;

 

On running the above code, we get the following output.

 

operators_arithmrtic.jpg

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