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AndreyMyslivets
Obsidian | Level 7

Hello!

I've got some problems with selecting right model/method in my analysis.

Two groups of animals (differ by "Treatment") were measured from 1-st to 42-nd day, one common value for each group was measured by each day (food consumption per day).

I need to compare this groups and I want to use ANCOVA with "Treatment" as fixed effect and "Day number" as covariate in the model.

There are many examples which contain covariates with some sort of randomness in their distribution (like weight, age, IQ, etc., where we can't directly control this variable).

But in our experiment we eliminate this variation by measuring groups day by day. Is it correct to use "Day number" as continious covariate?

Maybe the whole model is incorrect and you can suggest right one?

Best regards!

1 ACCEPTED SOLUTION

Accepted Solutions
SteveDenham
Jade | Level 19

OK, then we can trim things down some, rearrange and see what happens:

proc glimmix data=yourdata method=laplace;

class treatment day_no ;

model response_variable=treatment day_no;

random day_no/subject=treatment type=ar(1) ;

lsmeans treatment/diff;

run;

At least this way the standard errors reflect the within subject correlation.

Steve Denham

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6 REPLIES 6
SteveDenham
Jade | Level 19

What was measured on each day?  It looks to me like a repeated measures design, so something like:

proc glimmix data=yourdata;

class treatment day_no anml_no;

model response_variable=treatment|day_no/ddfm=kr2;

random day_no/residual type=ar(1) subject=anml_no;

random intercept/subject=anml_no;

lsmeans treatment/diff;

lsmeans treatment*day_no/slicediff=day_no;

run;

Steve Denham

AndreyMyslivets
Obsidian | Level 7

Hello Steve!

Thank you very much for answer! But it's impossible to use here a repeated measures design... in classical meaning.

I have just one average value of food consumption per day for each group, I haven't concrete subjects.

There is example of my data:

DayTreatAv. value
1treat 10.24
1treat 20.35
2treat 10.52
2treat 20.64
.........
41treat 15.47
41treat 25.20
42treat 15.31
42treat 25.43

Many thanks in advance!

Best wishes!

SteveDenham
Jade | Level 19

OK, then we can trim things down some, rearrange and see what happens:

proc glimmix data=yourdata method=laplace;

class treatment day_no ;

model response_variable=treatment day_no;

random day_no/subject=treatment type=ar(1) ;

lsmeans treatment/diff;

run;

At least this way the standard errors reflect the within subject correlation.

Steve Denham

AndreyMyslivets
Obsidian | Level 7

Thank you Steve!

I'm really beginner at using methods above PROC GLM.

When I tried to solve the problem I used this code:

proc glm data=mydata;

  class treatment;

  model response_variable=treatment day_no;

  lsmeans treatment;

run;

I planned to use day_no as covariate and to compare regression slopes.

Can you help me to understand what is my mistake?

Also I have some questions about your code.

1. Why did you use the GLIMMIX instead of, for example, MIXED?

2. You have use  Laplace's approximation method for your analysis. Are there any criterions for choosing what method to use? SAS help does not give any advises for practical using just technical details.

3. There is the same problem with covariance structure type. I've checked a lot of sources and usually authors don't give any recommendations for choosing the right one c.s. for one or another real problem.

That would be really helpful if you turn me in the right direction.

SteveDenham
Jade | Level 19

The danger in the method with proc glm and assuming day_no as a covariate is an assumption of linearity.  If your growth curve is linear, then that makes good sense.  However, consider two treatments that start at exactly the same place, and end at the same place.  In the first, the response goes up rapidly and then levels off (a bowl with the mouth down), while in the second the response is relatively flat until the end and then increases (same bowl with the mouth up).  A linear covariate will not distinguish between these two cases--you will get nearly identical estimates of the slope.

Other questions:

1. Why GLIMMIX? It's more versatile than MIXED, so we use it almost exclusively for mixed model (including repeated measures).

2.  I don't know what your response variable is--my guess is that it has a gaussian error.  I just got slightly better results with method=laplace and a G side parameterization than with the default pseudo-REML and an R side parameterization.  If your data has normally distributed errors, then the default is preferable.

3. Selecting covariance structures can get tricky, but for data with normally distributed errors, fit by default methods, using AICc is a good guide to choosing amongst various structures.

The idea of a semi-parametric approach to the day_no issue using a spline may be feasible, but I will need to explore my simulated data first.

Steve Denham

AndreyMyslivets
Obsidian | Level 7

Thanks to all, who tried to help!

I will try to summarize information.


Helpful comment from another source:

The assumptions for an ANCOVA or similar general linear models are that the residuals are normally distributed and homoscedastic, and that each observation is independent.

Although not the residuals, the clear, curvy shape of your scatterplot indicates almost certain temporal autocorrelation, and therefore non-independence of observations.


Pictures of my data:

5009f04d072f32f06453609955e0680a.png

So the plan to using Repeated Measures ANOVA or ANCOVA with day number as covariate wasn't so good...


I have two ways to solve this problem today:


1. Classical (for my job colleagues) way and suggested by Nestor Rohowsky here: "to take the differences between means of Treatment 1 and Treatment 2 at each time to evaluate departures from 0."

2. Using GLIMMIX like SteveDenham wrote here.

I can't say, that everething is clear for me in second method, but it becouse of my low quality of knowledge of MIXED and GLIMMIX, so I feel, that it is the right way.

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