id date_1 date_2 date_3
1 . 02/02/2012 01/01/2001
2 01/11/2009 2/10/2011 01/01/2004
3 01/08/2013 . 2/10/2012
4 11/10/2015 01/01/1998 26/12/2014
I am trying to the find the minimum of three dates but I have some missing information so I want to retain the minmum among the one that is avaiable:
output
1 01/01/2001
2 01/01/2004
3 02/10/2012
4 01/01/1998
The MIN function already handles this issue? So the following will do
data have;
informat date_1 date_2 date_3 ddmmyy10.;
input id date_1 date_2 date_3;
format date_1 date_2 date_3 ddmmyy10.;
datalines;
1 . 02/02/2012 01/01/2001
2 01/11/2009 2/10/2011 01/01/2004
3 01/08/2013 . 02/10/2012
4 11/10/2015 01/01/1998 26/12/2014
;
data want;
set have;
newvar = min(date_1,date_2,date_3);
format newvar ddmmyy10.;
run;
The MIN function already handles this issue? So the following will do
data have;
informat date_1 date_2 date_3 ddmmyy10.;
input id date_1 date_2 date_3;
format date_1 date_2 date_3 ddmmyy10.;
datalines;
1 . 02/02/2012 01/01/2001
2 01/11/2009 2/10/2011 01/01/2004
3 01/08/2013 . 02/10/2012
4 11/10/2015 01/01/1998 26/12/2014
;
data want;
set have;
newvar = min(date_1,date_2,date_3);
format newvar ddmmyy10.;
run;
Just to add, functions like min() can also accept ranges of variables which can make typing much easier when you have lots of variables:
newvar=min(of date_:);
Assumes of course all variables have same prefix (or you setup and array of them before).
Thank you!
It's finally time to hack! Remember to visit the SAS Hacker's Hub regularly for news and updates.
Learn how use the CAT functions in SAS to join values from multiple variables into a single value.
Find more tutorials on the SAS Users YouTube channel.
Ready to level-up your skills? Choose your own adventure.