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Ronein
Meteorite | Level 14

Hello

I have a data set with one row for each customer with 2 fields: CustID and YYYYMM (year month).

I want to create for each customer 12 rows with  information of 12 months  (till 11 months prior to YYYYMM)

What is the way ti create want data set via code that calculate it?

In real life I have 100,000 customers

 

Data have;
Input CustID YYYYMM;
cards;
1 202201
2 202303
;
Run;

Data want;
Input CustID Position YYYYMM;
cards;
1 0 202201
1 -1 202112
1 -2 202111
1 -3 202110
1 -4 202109
1 -5 202108
1 -6 202107
1 -7 202106
1 -8 202105
1 -9 202104
1 -10 202103
1 -11 202102
2 0 202303
2 -1 202302
2 -2 202301
2 -3 202212
2 -4 202211
2 -5 202210
2 -6 202209
2 -7 202208
2 -8 202207
2 -9 202206
2 -10 202205
2 -11 202204
;
Run;
1 ACCEPTED SOLUTION

Accepted Solutions
PaigeMiller
Diamond | Level 26
data want;
    set have;
    startyymm=input(put(yyyymm,6.),yymmn6.);    
    do i=0 to -11 by -1;
        yymm=intnx('month',startyymm,i);
        output;
    end;
    format yymm yymmn6.;
    drop i startyymm yyyymm;
run; 

 

 

NOTE: Always work with valid SAS date values, the number of days since 01JAN1960. Thus, we need to convert your variable YYYYMM to an actual valid SAS date value via the INPUT function.

--
Paige Miller

View solution in original post

3 REPLIES 3
PaigeMiller
Diamond | Level 26
data want;
    set have;
    startyymm=input(put(yyyymm,6.),yymmn6.);    
    do i=0 to -11 by -1;
        yymm=intnx('month',startyymm,i);
        output;
    end;
    format yymm yymmn6.;
    drop i startyymm yyyymm;
run; 

 

 

NOTE: Always work with valid SAS date values, the number of days since 01JAN1960. Thus, we need to convert your variable YYYYMM to an actual valid SAS date value via the INPUT function.

--
Paige Miller
Ronein
Meteorite | Level 14

Great, here is the required solution by your code advice

data want (Rename=(i=Position));
    set have;
    startyymm=input(put(yyyymm,6.),yymmn6.);    
    do i=0 to -11 by -1;
        yymm=intnx('month',startyymm,i);
        output;
    end;
    format yymm yymmn6.;
    drop  startyymm yyyymm;
run; 
PaigeMiller
Diamond | Level 26

Even simpler:

 

data want;
    set have;
    startyymm=input(put(yyyymm,6.),yymmn6.);    
    do position=0 to -11 by -1;
        yymm=intnx('month',startyymm,position);
        output;
    end;
    format yymm yymmn6.;
    drop  startyymm yyyymm;
run; 
--
Paige Miller

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