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alaxman
Obsidian | Level 7

Hello, 

 

I have the following example data. I would like to write a conditional statement that encompasses the following: 


If last.enrolid and med_name = N;
and lag(svcdate_new) gt svcdate_orig
then I would like to replace the lag(svcdate_new) with the svcdate_orig of the "N" medication. 

The "N" medication will always be the last medication for each unique patient. 

 

For the example below, since 7/12/14 (the lag svcdate_new) is greater than 6/19/14 svcdate_orig of the "N" medication, then I would like to replace the 7/12/14 with 6/19/14.  

 

 

data have(label='Prescription Data');
   /*length id $7;*/
   infile datalines truncover;
   input patient_id:$4. med_name:$10. svcdate_orig:MMDDYY8. svcdate_new:MMDDYY8.;
   format svcdate_orig:MMDDYY8. svcdate_new:MMDDYY8.;
   
Datalines;
1 B 1/13/14 1/13/14
1 B 2/10/14 2/12/14
1 B 2/16/14 2/22/14
1 B 3/7/14 3/14/14
1 B 4/3/14 4/13/14
1 B 5/3/14 5/13/14
1 B 5/27/14 6/12/14
1 B 6/6/14 6/27/14
1 B 6/16/14 7/12/14
1 N 6/19/14 7/13/14
;
proc sort data = have;
 by patient_id svcdate_orig;
run;

What I want the code to do (in red below):

Datalines; 1 B 1/13/14 1/13/14 1 B 2/10/14 2/12/14 1 B 2/16/14 2/22/14 1 B 3/7/14 3/14/14 1 B 4/3/14 4/13/14 1 B 5/3/14 5/13/14 1 B 5/27/14 6/12/14 1 B 6/6/14 6/27/14 1 B 6/16/14 6/19/14 1 N 6/19/14 7/13/14

Thank you for any insights you may have! 

1 ACCEPTED SOLUTION

Accepted Solutions
Ksharp
Super User
data have(label='Prescription Data');
   /*length id $7;*/
   infile datalines truncover;
   input patient_id:$4. med_name:$10. svcdate_orig:MMDDYY8. svcdate_new:MMDDYY8.;
   format svcdate_orig:MMDDYY8. svcdate_new:MMDDYY8.;
   
Datalines;
1 B 1/13/14 1/13/14
1 B 2/10/14 2/12/14
1 B 2/16/14 2/22/14
1 B 3/7/14 3/14/14
1 B 4/3/14 4/13/14
1 B 5/3/14 5/13/14
1 B 5/27/14 6/12/14
1 B 6/6/14 6/27/14
1 B 6/16/14 7/12/14
1 N 6/19/14 7/13/14
;
proc sort data = have;
 by patient_id svcdate_orig;
run;

data temp;
set have ;
by patient_id;
if last.patient_id and med_name='N' and 
lag(patient_id)=patient_id and lag(svcdate_new) gt svcdate_orig then
new=svcdate_orig;
format new mmddyy8.;
run;
data want(drop=_: new);
merge temp temp(firstobs=2 keep=patient_id new rename=(patient_id=_pid ));
if patient_id=_pid and not missing(new) then svcdate_new=new;
run;

View solution in original post

6 REPLIES 6
alaxman
Obsidian | Level 7

Here is what I want the code to do (the above did not come out correctly!) - in red below

 

1

B

1/13/14

1/13/14

1

B

2/10/14

2/12/14

1

B

2/16/14

2/22/14

1

B

3/7/14

3/14/14

1

B

4/3/14

4/13/14

1

B

5/3/14

5/13/14

1

B

5/27/14

6/12/14

1

B

6/6/14

6/27/14

1

B

6/16/14

6/19/14

1

N

6/19/14

7/13/14

FreelanceReinh
Jade | Level 19

Hello @alaxman,

 


@alaxman wrote:

The "N" medication will always be the last medication for each unique patient. 


If med_name="N" reliably implies last.patient_id (in a data step with by patient_id ...), you can use a look-ahead merge like this:

data want(drop=_:);
merge have have(firstobs=2 keep=patient_id med_name svcdate_orig
                rename=(patient_id=_pid med_name=_mn svcdate_orig=_so));
if patient_id=_pid & _mn='N' & svcdate_new gt _so then svcdate_new=_so;
run;

Otherwise, you would need to look one observation further ahead to ensure that the med_name="N" observation is also the last of the patient:

data want(drop=_:);
merge have have(firstobs=2 keep=patient_id med_name svcdate_orig
                rename=(patient_id=_pid med_name=_mn svcdate_orig=_so))
           have(firstobs=3 keep=patient_id rename=(patient_id=_pid2));
if patient_id=_pid~=_pid2 & _mn='N' & svcdate_new gt _so then svcdate_new=_so;
run;
Ksharp
Super User
data have(label='Prescription Data');
   /*length id $7;*/
   infile datalines truncover;
   input patient_id:$4. med_name:$10. svcdate_orig:MMDDYY8. svcdate_new:MMDDYY8.;
   format svcdate_orig:MMDDYY8. svcdate_new:MMDDYY8.;
   
Datalines;
1 B 1/13/14 1/13/14
1 B 2/10/14 2/12/14
1 B 2/16/14 2/22/14
1 B 3/7/14 3/14/14
1 B 4/3/14 4/13/14
1 B 5/3/14 5/13/14
1 B 5/27/14 6/12/14
1 B 6/6/14 6/27/14
1 B 6/16/14 7/12/14
1 N 6/19/14 7/13/14
;
proc sort data = have;
 by patient_id svcdate_orig;
run;

data temp;
set have ;
by patient_id;
if last.patient_id and med_name='N' and 
lag(patient_id)=patient_id and lag(svcdate_new) gt svcdate_orig then
new=svcdate_orig;
format new mmddyy8.;
run;
data want(drop=_: new);
merge temp temp(firstobs=2 keep=patient_id new rename=(patient_id=_pid ));
if patient_id=_pid and not missing(new) then svcdate_new=new;
run;
alaxman
Obsidian | Level 7
Thank you !!
alaxman
Obsidian | Level 7

@Ksharp Thanks very much, your code works well! What if I wanted to add an additional condition where I also want the lag(svcdate_orig) to = 0. All other conditions are the same. Would you just add this requirement to this code or create a new data step accordingly? thanks so much!

Ksharp
Super User

You want this condition be 'AND' or 'OR' ?

Assuming you want 'OR' . Here is:

 

data temp;
set have ;
by patient_id;
if last.patient_id and med_name='N' and 
lag(patient_id)=patient_id and 
(lag(svcdate_new) gt svcdate_orig  or lag(svcdate_orig)= 0  ) then
new=svcdate_orig;
format new mmddyy8.;
run;

 

 

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