I have a table as follows
and i need below output
data want; merge have ( rename=(f2=acc_status) where=(f1 = "ACC_STATUS") ) have ( rename=(f2=acc_status_desc) where=(f1 = "ACC_STATUS_DESC") ) ; drop f1; run;
This doesn't seem like a transpose to me. This ought to work (although I have made a lot of assumptions)
data want; merge have(where=(f1='ACC_STATUS') rename=(f2=acc_status)) have(where=(f1='ACC_STATUS_DESC') rename=(f2=acc_status_desc)); drop f1; run;
Yes, it looks rather like a table transformation from long format to wide format, than a Transpose.
To use PROC TRANSPOSE you will need to have another variable that indicates which rows go together.
data have; row+1; input f1 :$32. f2 :$32. ; if f1 ne lag(f1) then row=1; cards; ACC_STATUS 1 ACC_STATUS 1 ACC_STATUS 1 ACC_STATUS 3 ACC_STATUS 1 ACC_STATUS_DESC Closed ACC_STATUS_DESC Active ACC_STATUS_DESC Active ACC_STATUS_DESC Active ACC_STATUS_DESC Active ;
Then you can use that as a BY variable.
proc sort; by row f1 ; run; proc transpose data=have out=want(drop=_name_); by row; id f1; var f2; run;
ACC_ ACC_STATUS_ Obs row STATUS DESC 1 1 1 Closed 2 2 1 Active 3 3 1 Active 4 4 3 Active 5 5 1 Active
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