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jcis7
Pyrite | Level 9

Hello,

I'm getting teh folloiwng error: Invalid third argument to function SUBSTR

The variable cdcode is text and 14 characters long.

Here's my code:


data new;

     set old;

     length co $2 dist $5 sch $7;

     co=substr(cdcode, 1,2);

     dist=substr(cdcode, 3,7);

     sch=substr(cdcode,8,14);

run;

Can you help me understand why I'm getting this message?

Thanks!

1 ACCEPTED SOLUTION

Accepted Solutions
Doc_Duke
Rhodochrosite | Level 12

RTFM.  Your code should read

sch=substr(cdcode,8,7);

View solution in original post

4 REPLIES 4
Doc_Duke
Rhodochrosite | Level 12

RTFM.  Your code should read

sch=substr(cdcode,8,7);
jcis7
Pyrite | Level 9

Thank you!  Is it because it's the last part of the cdcode that it's 7 instead of 14? 

Doc_Duke
Rhodochrosite | Level 12

from the reference manual

"Interaction:If length is zero, a negative value, or larger than the length of the expression that remains in string after position, SAS extracts the remainder of the expression. SAS also sets _ERROR_ to 1 and prints a note to the log indicating that the length argument is invalid."

jcis7
Pyrite | Level 9

Thank you!!

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