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data have;
input date $ 10.;
cards;
2017-01-01
2016-10
2010-11
;
run;

Required:

2017-01-01
2016-10-31
2010-11-30
1 ACCEPTED SOLUTION

Accepted Solutions
Reeza
Super User
data want;
set have;

if length(date)<10 then date_num =intnx('month', input(cats(date, '-01'), yymmdd10.), 0, 'e');

else date_num = input(date, yymmdd10.);
format date_num date9.;


run;

View solution in original post

7 REPLIES 7
novinosrin
Tourmaline | Level 20
data have;
input date $ 10.;
cards;
2017-01-01
2016-10
2010-11
;
run;

data want;
set have;
new_date=input(date,anydtdte21.);
if length(date)=7 then new_Date=intnx('month',new_date,0,'e');
format new_date yymmdd10.;
run;
Reeza
Super User
data want;
set have;

if length(date)<10 then date_num =intnx('month', input(cats(date, '-01'), yymmdd10.), 0, 'e');

else date_num = input(date, yymmdd10.);
format date_num date9.;


run;
rajeshalwayswel
Pyrite | Level 9

Thanks to both. but the year is leap year in this scenario what would be the solution?

novinosrin
Tourmaline | Level 20

Please test and let me know

Reeza
Super User

Leap year doesn't matter.

 


@rajeshalwayswel wrote:

Thanks to both. but the year is leap year in this scenario what would be the solution?


 

ballardw
Super User

@rajeshalwayswel wrote:

Thanks to both. but the year is leap year in this scenario what would be the solution?


SAS knows which years are leap years, at least through 19999 the last time looked, and 'e' option in intnx takes that into account.

 

Yes I said 19999. I had to demonstrate this multiple times during Y2K worries about the data I was storing in SAS. The date formats don't display properly because of the 5-digit year but the date functions work just fine.

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