How to extract year and month from date in SAS?

[afiqcjohari]

I have date variables in the form of YYYY-MM-DD, stored in tables.

How do I extract the Year?

Basically I just want to do a simple SQL 

such as, select * from table where YEAR(date) = 2017;

Thanks!

[gamotte · Accepted solution]

Hello,

the function you are looking for is year() as you guessed correctly, but your data has to be in

a date format.

data have;
format dt yymmdd10.;
input dt yymmdd10.;
datalines;
2016-05-21
2017-08-12
2014-03-02
;
run;

data want;
set have;
where year(dt)=2017;
run;

Edit: If you have strings instead :

data want;
set have;
where year(input(dt,yymmdd10.))=2017;
run;

[katkarparam]

Do you have another solution to change observation value at
one shot for all rather than one by one. suppose i have billions of record...

[RW9]

Are you sure its a SAS numeric date, i.e. it is a number if you remove the format.  If so then year(), if it is character which I suspect, then just use:

where scan(date,1,"-")="2017";

[afiqcjohari]

The date is in this format YYMMDD10. 

[afiqcjohari]

Can I create a new column year within proc sql?

proc sql;
select input(thedate,yymmdd10.) as myyear
from mytable;
quit;

I tried this but doesn't seem to work.

[Singla14]

Hi , I have input file having year ( let's say 2015 to 2017 YYYY) .
I am trying to fetch system year ( year(today())
And then compare year from input file to fetched year.
If matches , those rows should come in output.

If comparison for years is not working ..Have tried reading input year in chat..Integer both..But nothing working.
Can some one please help..Urgent !

[RW9]

This question is answered and closed.  Please start a new thread providing example data in the form of a datastep and what the output should look like.