## substring from the right

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Super Contributor
Posts: 409

# substring from the right

Hi,  is there a quick way to substring from the right but skip a few digits.

If I have 2345001  I want to get 2345 .. I want to only remove the last 3 digits...  the length of the field is not uniform, soucl be 8 digits or 10 or 9, etc.  but th eonly thing sore sure is that I want to remove the last 3 digits..  Thanks

Accepted Solutions
Solution
‎04-02-2014 02:51 PM
Posts: 5,539

## Re: substring from the right

myStr =  substr(myStr, 1, length(myStr) - 3);

PG

All Replies
Solution
‎04-02-2014 02:51 PM
Posts: 5,539

## Re: substring from the right

myStr =  substr(myStr, 1, length(myStr) - 3);

PG
Occasional Contributor
Posts: 12

## Re: substring from the right

Another approach in these sorts of situations is to use the substring function with the reverse function

mystr =  reverse(substr(strip(reverse(mystr)),4));

Super User
Posts: 8,119

## Re: substring from the right

Is your variable a number or a character string?

137  data _null_;

138    x=2345001 ;

139    y=int(x/1000);

140    put x= y=;

141  run;

x=2345001 y=2345

Posts: 3,167

## Re: substring from the right

The more, the merrier:

data _null_;

mystr="2345001";

new_str=prxchange('s/(^\w+)(\w{3}\$)/\$1/',-1,strip(mystr));

put mystr= new_str=;

run;

Haikuo

Posts: 5,539

## Re: substring from the right

The simpler, the better :smileysilly:

data _null_;

mystr="  2345001     ";

new_str = prxchange('s/\d{3}\s*\$//', 1, mystr);

put mystr= new_str=;

run;

PG

PG
Posts: 3,167

## Re: substring from the right

Better indeed!

Haikuo

Occasional Contributor
Posts: 12

## Re: substring from the right

Might be better use of prxchange, but not exactly readable nor intuitively obvious what the code is doing.

I'd want a comment explaining what was being done and why so that my BAU support junior could understand what the code was doing.

Posts: 5,539

## Re: substring from the right

It reads: Replace (s) a succession of exactly 3 ({3}) digits (\d) followed by any amount (*) of white space (\s) and occuring at the end of the string (\$) with nothing(//). Do this only once.

PG

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