date

[SAS83]

how to strip out year from this field.

It is in datetime format.

19JAN2006:17:14:33.072000

Thanks in advance..

[yaswoman]

You can use the DATEPART function.
YEAR=DATEPART(yourdate);

I think that is the right syntax.

[SPR]

Hello SAS83,

This is a possible solution:
[pre]
data i;
dt="19JAN2006:17:14:33.072000"dt;
year=YEAR(DATEPART(dt));
format dt datetime.;
run;
[/pre]
Sincerely,
SPR

[SAS83]

Thank you !!