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JAR
Obsidian | Level 7 JAR
Obsidian | Level 7

Dear All,

I would like to learn how to calculate % change, when two strings are compared.

Here is the original file:

1RATCAT
2BELLBALL
3TIMETOM

As there is only one character that is different in the first observation, it should return 1/3 %(number of deviation / total number of char in the original).

Desired output is something like this:

1RATCAT33
2BELLBALL25
3TIMETOM50

Thanks in advance,

Jijil Ramakrishnan

4 REPLIES 4
stat_sas
Ammonite | Level 13

Try this for the desired output.

data have;
input obs var1 $ var2 $;
datalines;
1 RAT CAT
2 BELL BALL
3 TIME TOM
;

data want;
set have;

do i=1 by 1 while(substr(var1,i,1) ne ' ');
if index(var2,substr(var1,i,1))>0 then cnt+1;
output;
end;
cnt=0;
run;

data final (drop=i cnt);
set want;
by obs;
if last.obs;
diff=(i-cnt)/i*100;
format diff 8.0;
run;

JAR
Obsidian | Level 7 JAR
Obsidian | Level 7

Thank you so much.

PGStats
Opal | Level 21

Approximate matches between strings is an already well researched topic. SAS provides you with many tools in that area. Please look at SAS functions COMPGED, COMPLEV, SOUNDEX, and SPEDIS.

PG

PG
JAR
Obsidian | Level 7 JAR
Obsidian | Level 7

Thanks a lot!

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