Solved
Contributor
Posts: 43

# Simple, if var = 1 then restart count

Hi, i have a dataset with people rolling a dice, and i need to label them with a game number

I have a varible called trialCount. This goes from 1 to 13, and everytime it equals one, its a new game number.

Basically this is the stucture i have - except for game number:

trialCount     totalTrialCount     gamenumber (Dont have, but want!)

1                    1                         1

2                    2                         1

3                    3                         1

4                    4                         1

1                    5                         2

2                    6                         2

1                    7                         3

1                    8                         4

1                    9                         5

2                    10                       5

3                    .                         5

4                    .                         .

5                                              .

6

7

.

.

So basically what i would like is something conceptually like:

When trialcount = 1

then gamenumber = "some loop that counts what game number we are at, and puts that number in"

until trialcount = 1 again, then start over

I can't really work this out. I can do a simple count + 1, first.count, but that dosen't really work here.

Hope you understand where im coming from!

Thanks

toby

Accepted Solutions
Solution
‎10-29-2012 02:09 PM
PROC Star
Posts: 8,164

## Re: Simple, if var = 1 then restart count

why not just?:

if trialCount eq 1 then GameNumber+1;

All Replies
Solution
‎10-29-2012 02:09 PM
PROC Star
Posts: 8,164

## Re: Simple, if var = 1 then restart count

why not just?:

if trialCount eq 1 then GameNumber+1;

Posts: 3,167

## Re: Simple, if var = 1 then restart count

Exactly, or equally:

Haikuo

Contributor
Posts: 43

## Re: Simple, if var = 1 then restart count

God i think i had too much coffee this evening.

Thanks for pointing out the obvious.

T

🔒 This topic is solved and locked.