Help using Base SAS procedures

SUM and Percent

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Occasional Contributor
Posts: 14
Accepted Solution

SUM and Percent

Hello,

How to create table like this one below. Sum first and second value and than from each value get rate. Is there anybody who know code for this problem?

 

My data

 

dateValueED
2016128284200
20161262101
2016123159510
2016126411

 

Want data

 

dateValueEDSumRate
2016128284200834630,74%
20161262101  
2016123159510316590,20%
2016126411  

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Solution
‎07-11-2017 04:35 AM
Super User
Posts: 6,977

Re: SUM and Percent

data have;
input date $ value e d;
cards;
201612 82842 0 0
201612 621 0 1
201612 31595 1 0
201612 64 1 1
;
run;

data want;
merge
  have
  have (firstobs=2 rename=(e=_e d=_d date=_date value=_value))
;
if d = 0 and _date = date and _e = e
then do;
  sum = value + _value;
  rate = _value / sum;
end;
format rate percent7.2;
keep date value e d sum rate;
run;

proc print data=want noobs;
run;

Result:

 date     value    e    d     sum        rate

201612    82842    0    0    83463     0.74% 
201612      621    0    1        .      .    
201612    31595    1    0    31659     0.20% 
201612       64    1    1        .      .    
---------------------------------------------------------------------------------------------
Maxims of Maximally Efficient SAS Programmers

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Super User
Posts: 6,977

Re: SUM and Percent

[ Edited ]
data want;
merge
  have
  have (firstobs=2 rename=(e=_e d=_d date=_date value=_value))
;
if d = 0 and _date = date and _e = e
then do;
  sum = value + _value;
  rate = _value / sum;
end;
format rate percent7.2;
keep date value e d sum rate;
run;

Edit: added a closing bracket in the merge statement, to correct a syntax error.

---------------------------------------------------------------------------------------------
Maxims of Maximally Efficient SAS Programmers
Occasional Contributor
Posts: 14

Re: SUM and Percent

This is result of this code...it doesnt work properly.

dateValueEDSumRate
20161262100124250.0%
2016123159501..   
201612641012850.0%
2016126411..   
Solution
‎07-11-2017 04:35 AM
Super User
Posts: 6,977

Re: SUM and Percent

data have;
input date $ value e d;
cards;
201612 82842 0 0
201612 621 0 1
201612 31595 1 0
201612 64 1 1
;
run;

data want;
merge
  have
  have (firstobs=2 rename=(e=_e d=_d date=_date value=_value))
;
if d = 0 and _date = date and _e = e
then do;
  sum = value + _value;
  rate = _value / sum;
end;
format rate percent7.2;
keep date value e d sum rate;
run;

proc print data=want noobs;
run;

Result:

 date     value    e    d     sum        rate

201612    82842    0    0    83463     0.74% 
201612      621    0    1        .      .    
201612    31595    1    0    31659     0.20% 
201612       64    1    1        .      .    
---------------------------------------------------------------------------------------------
Maxims of Maximally Efficient SAS Programmers
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