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yeaforme
Calcite | Level 5

Probably a very newbie question, but I can't seem to get anything to work.

I have an existing dataset (got from someone else) with a column of "dates" with values such as 199301 (meaning January of 1993).  The values appear to be stored as BEST 12, though, so that when I try to use them as dates I get a whole bunch of very funny results.

My understanding is that I need to change the numbers to characters and then read them back in as SAS dates, but haven't had any luck.  I've tried code like the following, but either get errors or the new dates come out as missing:

D2 = input(put(yyyymm, Z6.) , YYMMDD6.);

Any ideas?  Really, all I want to do is change the 199301 (stored as Best 12) into 199301 (stored as a date).

1 ACCEPTED SOLUTION

Accepted Solutions
Reeza
Super User

The underlying date will actually be January 1, 1993

Right idea though, wrong execution.

data have;

input date_num;

cards;

199301

199302

199303

199304

;

run;

data want;

set have;

date_format=input(put(date_num, 6. -l), yymmn6.);

format date_format yymmn6.;

run;

View solution in original post

3 REPLIES 3
Haikuo
Onyx | Level 15

new_date=input(put(date,6.),yymmn6.);

Haikuo

Update: this will assume you the first day of the month. if you want some other days, you want to take a look at MDY() plus substr().

Reeza
Super User

The underlying date will actually be January 1, 1993

Right idea though, wrong execution.

data have;

input date_num;

cards;

199301

199302

199303

199304

;

run;

data want;

set have;

date_format=input(put(date_num, 6. -l), yymmn6.);

format date_format yymmn6.;

run;

yeaforme
Calcite | Level 5

Thanks - worked like a charm.

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