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10-23-2014 07:44 AM

Hi,

I am in need of some assistance here. I am trying to create a dataset with frequencies, as mapped over several variables/attributes.

My 'have' set is as follows:

data have;

input ID a b c d e f END;

cards;

1 X X X Y X Z K

922 X Y Y Z Y X K

33 W Z Y Y X X K

12 X X W W X Y F

;

run;

The value domain of each variable/attribute *a .. f* is the same.

From this dataset 'have' I wish to create a new set where each variable is the frequency of that value in 'have'.

For instance, if we are to use the above dataset 'have', the resultant 'want' is:

data want;

input ID X Y Z W END;

cards;

1 4 1 1 0 K

922 2 3 1 0 K

33 2 2 1 1 K

12 3 1 0 2 F

;

run;

Can you give me some suggestions on how to accomplish this feat?

Accepted Solutions

Solution

10-23-2014
08:18 AM

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Posted in reply to Dess

10-23-2014 08:18 AM

Your input data with replicates represented in variables only serves to obfuscate the true task. I would relieve the burden posed by variables a--f and concentrate on their values.

input ID (a b c d e f END)(:$1.);

cards;

1 X X X Y X Z K

922 X Y Y Z Y X K

33 W Z Y Y X X K

12 X X W W X Y F

;;;;

by id notsorted;

var a--f;

class id col1;

output out=counts;

by id notsorted;

id col1;

var _freq_;

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Posted in reply to Dess

10-23-2014 08:00 AM

Hi,

data have;

infile datalines dlm="," missover;

input id a $ b $ c $ d $ e $ f $ END $;

datalines;

1,X,X,X,Y,X,Z,K

922,X,Y,Y,Z,Y,X,K

33,W,Z,Y,Y,X,X,K

12,X,X,W,W,X,Y,F

;

run;

data want (keep=id res1-res4 end);

set have;

array cols{6} a b c d e f;

array res{4} 8. (0,0,0,0);

array test{4} $20. ('X','Y','Z','W');

do i=1 to 4;

do j=1 to 6;

if cols{j}=test{i} then res{i}=sum(res{i},1);

end;

end;

run;

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10-27-2014 09:06 AM

Thank you very much.

The procedure you listed did unfortunately count not only the individual frequencies, but accumulated them in each subsequent observation. It did however prove very helpful in showing me how it could be done. So thank you.

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Posted in reply to Dess

10-23-2014 08:01 AM

data want (keep=ID X Y Z W);

set have;

array field {*} a b c d e f;

X = 0; Y = y; Z = 0; W = 0;

do i = 1 to 6;

select (field{i});

when ('X') X = X + 1;

when ('Y') Y = Y + 1;

when ('Z') Z = Z + 1;

when ('W') W = W + 1;

end;

end;

run;

---------------------------------------------------------------------------------------------

Maxims of Maximally Efficient SAS Programmers

Maxims of Maximally Efficient SAS Programmers

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Posted in reply to KurtBremser

10-27-2014 09:09 AM

This was a great way to do it I think. There was however an issue with counting, as expanding on your solution caused some errors regarding 'conversion from integer to character', though it is probable that this was due to my understanding rather than any irregularity in the procedure.

Thank you for the great answer.

Solution

10-23-2014
08:18 AM

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Posted in reply to Dess

10-23-2014 08:18 AM

Your input data with replicates represented in variables only serves to obfuscate the true task. I would relieve the burden posed by variables a--f and concentrate on their values.

input ID (a b c d e f END)(:$1.);

cards;

1 X X X Y X Z K

922 X Y Y Z Y X K

33 W Z Y Y X X K

12 X X W W X Y F

;;;;

by id notsorted;

var a--f;

class id col1;

output out=counts;

by id notsorted;

id col1;

var _freq_;

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Posted in reply to data_null__

10-27-2014 09:11 AM

This worked right off the bat. Excellent and elegant answer. Thank you for the help.