08-07-2015 06:04 AM
I have character date in YYMM format.(Column Name EXPDATE)
e.g. '2004' which means April 2020
'2104' which means April 2021
'2204' which means April 2022
'2304' which means April 2023
How to convert it into date format ?
Being a beginner in SAS I googled the same and use below mentioned logic
format exp date9.;
Exp = intnx('month', input(put(EXPDATE,4.), yymmn4.), 1)-1;
Which gives me output 30Apr1920 instead of 2020 and similarly for all remaining values where YY value is above 20.
Please help me to resolve the same.
Business Analyst,HDFC Bank
08-07-2015 07:48 AM
08-07-2015 07:48 AM
08-07-2015 08:40 AM
Your problem is YEARCUTOFF I expect it is the same as mine which defaults to 1920 set it to something greater than your largest 2 digit year; Also you don't need PUT(EXPDATE,4.) as EXPDATE is already character, or so you say. If you want the last day of the month EXP you can advance by 0 and use E for the alignment option. This it looks like you know how INTNX works.
08-07-2015 08:13 AM
Note sure why you are getting the wrong century, but it is not hard to add the century back in. Is the existing variable character or numeric? You text says it is character but your example code is treating it as numeric. If it is numeric then convert it to text using the Z4. format to preserve any leading zeros.
input text_date $4.;
format num_date: yymmdd10.;
put (_all_) (=);
text_date=2004 num_date1=2020-04-01 num_date2=2020-04-01 num_date3=2020-04-01 num_date4=2020-04-01
text_date=2104 num_date1=2021-04-01 num_date2=2021-04-01 num_date3=2021-04-01 num_date4=2021-04-01
text_date=2204 num_date1=2022-04-01 num_date2=2022-04-01 num_date3=2022-04-01 num_date4=2022-04-01
text_date=2304 num_date1=2023-04-01 num_date2=2023-04-01 num_date3=2023-04-01 num_date4=2023-04-01
08-07-2015 11:02 AM
Personal rant: Anyone still writing 2 digit years deserves many lashes with a wet spaghetti noodle or similar chastisement.
Of course I may be too sensitive after Y2K reprogramming and storing data from the early 60's.
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