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Calculating mean + 1sd

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Contributor
Posts: 37

Calculating mean + 1sd

 

 

My data looks like

 

X     pct_Elderly     

1      1.1

0       2.0

1       3.0

0       4.8

1        9.5

0       0.9

0       3.3

1       70.6

1      19.8

 

I need to populate a table like:  

                                  X
Total  5
high elderly(+1 SD)  ?

 

All suggestions welcomed!

Respected Advisor
Posts: 3,070

Re: Calculating mean + 1sd

Posted in reply to pmpradhan

PROC MEANS

--
Paige Miller
Super User
Posts: 23,791

Re: Calculating mean + 1sd

Posted in reply to pmpradhan
What are the rules? What exactly are you having trouble with? Your last question had an example of PROC MEANS and getting output, does that not work here as well for some reason?


Contributor
Posts: 37

Re: Calculating mean + 1sd

Posted in reply to pmpradhan

I was thinking whether it is :

 

Procedure 1:

proc means data=have;

var pct_elderly;

where x=1;

run;

 

or 

Procedure 2:

data want;

set have;

high_elderly=(pct_elderly>=means+sd);

run;

 

proc freq data=want;

tables high_elderly;

where x=1;

run;

Super User
Posts: 23,791

Re: Calculating mean + 1sd

Posted in reply to pmpradhan

Those are very different. Based on the data you presented, what number are you expecting? What are the business rules?

 

For the second approach, I don't see the mean/sd so not sure where you're expecting that to come from and I wouldn't expect that to work. Does it work, or return errors?

 

 

Respected Advisor
Posts: 3,070

Re: Calculating mean + 1sd

Posted in reply to pmpradhan

@pmpradhan wrote:

I was thinking whether it is :

 

Procedure 1:

proc means data=have;

var pct_elderly;

where x=1;

run;

 

or 

Procedure 2:

data want;

set have;

high_elderly=(pct_elderly>=means+sd);

run;

 

proc freq data=want;

tables high_elderly;

where x=1;

run;


Did you even try these? Do they produce the answer you want? If not, state clearly what is missing from these answers.

 

Specifically, what is wrong with your Procedure 1? It seems like it does what you are asking (although I'm not 100% clear on what you are asking)

--
Paige Miller
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